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vredina [299]
3 years ago
11

rectangle q has an area of 2 square units thea drew scaled version and labled it rectangle r what scale factor did thea use to g

o from q to r
Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

<em>It has been given that Rectangle Q has an area of 2 square units.</em>

<em>Thea Drew a scaled version of Rectangle Q and marked it as R.</em>

<em>As you must keep in mind If we draw scaled copy of pre-image, then the two images i.e Pre-image and Image are similar.</em>

<em>As you have not written what is the scale factor of transformation</em>

<em>Suppose , Let the Scale factor of transformation= k</em>

<em>Rectangle Q = Pre -image, Rectangle R= Image</em>

<em>If, Pre-Image < Image , then scale factor is k >1.</em>

<em>But If, Pre-Image > Image , then Scale factor will be i.e lies between, 0<k<1.</em>

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Answer:

S= 5/2

Step-by-step explanation:

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3 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. (If an answer does not exist, enter DNE.)
vodka [1.7K]

Answer:

absolute max is 120 and absolute min is -8

Step-by-step explanation:

Find critical numbers

f'(x) = 3x^2 - 12x + 9 = 0

= 3(x^2 - 4x + 3) = 0

3(x-3)(x-1) = 0

(x-3) = 0 or (x-1)=0

x = 1,3

Test them!

x<1     Sign of f' on this interval is positive

1<x<3 Sign of f' on this interval is negative

x>3    Sign of f' on this interval is positive

f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.

f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.

Test the endpoints to find the absolute max and min.

f(-1) = -8

f(1) = 12

f(3) = 8

f(7) = 120

The absolute maximum value of f is 120 and the absolute minimum value of f is -8.

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3 years ago
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6x-4y=16
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2 years ago
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Answer:

A: Explanation: The surface area of a 3-D object is the sum of all the areas of all the 2-D surfaces of the object; so, its unit is the same as that of area. The SI unit of area is square metre (m2)

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