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Brut [27]
3 years ago
14

The key club made$192 at their candle sale. They dold round candles for $4 and square candles for $6. If they sold twice as many

sqaure candles as round ones, how many of each type of candle did the key club sell?
Mathematics
2 answers:
frez [133]3 years ago
5 0
They sold 22 square candles and 11 round candles
postnew [5]3 years ago
3 0

Answer:

The real answer is 12 round and 24 square candles. The top answer is wrong because she just guessed.

Step-by-step explanation:

4r+6s=192

s=2r

Solve:

4r+6(2r)=192

4r+12r=192

Combine like terms

16r=192

r=12

s=2(12)

s=24

12 round candles and 24 square candles

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Find the missing side.<br> Round to the nearest tenth.<br> For all 4 pics
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Answer:

1st pic) 17.8

2nd pic) 16.8

3rd pic) 9.1

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Step-by-step explanation:

<u>1st pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) Cos 27 (cos 27 = 0.89) = \frac{x}{20}

(new equation) 0. 89 = \frac{x}{20}

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<u>2nd pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write equation) tan 40 (tan 40 = 0.84) = \frac{32}{x}

(new equation) 0.84 =  \frac{32}{x}

(multiply 32 on both sides) 0.84 x 20 =  \frac{32}{x} x 20

(solve) 16.8 = x

<u>3rd pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) cos 55 (cos 55 = 0.57) = \frac{16}{x}

(new equation) 0.57 = \frac{16}{x}

(multiply 16 on both sides) 0.57 x 16 = \frac{16}{x} x 16

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<u>4th pic:</u> tan = \frac{adjacentx}{hypothenuse}

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(new equation) 0.90 = \frac{x}{15}

(multiply 15 on both sides) 0.90 x 15 = \frac{x}{15} x 15

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