Answer:
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Step-by-step explanation:
5z^2−9z=−7z−5
We need to get all the terms on one side (set the right side equal to zero)
Add 7z to each side
5z^2−9z+7z=−7z+7z−5
5z^2−2z=−5
Add 5 to each side
5z^2−2z+5=−5 +5
5z^2−2z+5=0
This is in the form
az^2 +bz+c = 0 so we can use the quadratic formula
where a = 5 b = -2 and c = 5
-b± sqrt(b^2-4ac)
-------------------------
2a
-(-2)± sqrt((-2)^2-4(5)5)
-------------------------
2(5)
2± sqrt(4-100)
-------------------------
10
2± sqrt(-96)
-------------------------
10
2± sqrt(16)sqrt(-1) sqrt(6)
-------------------------
10
2± 4i sqrt(6)
-------------------------
10
1/5 ± 2/5 i sqrt(6)
Splitting the ±
1/5 + 2/5 i sqrt(6) = .2 + .98i
1/5 - 2/5 i sqrt(6) = .2 - .98i
Answer:
131x
Step-by-step explanation:
7x² + 6x + 9x² - 5x
49x + 6x + 81x - 5x
136x - 5x
131x
Answer:
4 cm
Step-by-step explanation:
Both the area of a square and the area of a rectangle can be found by multiplying length x width. Because all of the sides of a square are equal, you get 64 when you multiply two sides together to find the area.
Since the rectangle has the same area as the square, that means the rectangle's width has to be a number that equals 64 when multiplied by 16.
So, 64/16 equals 4.
Please mark as brainliest ;)
Answer:
The center of the circle is (6 , 3)
Step-by-step explanation:
∵ The vertices of Δ EFG are E (4 , 4) , F (4 , 2) , G (8 , 2)
∵ The x-coordinates of E and E are equal ∴ EF is vertical
∵ The y-coordinates of F and G are equal ∴ FG is horizontal
∴ m∠EFG = 90°
∵ The circle is circumscribed about Δ EFG
∴ E , F , G lie on the circle
∵ m∠F = 90°
∴ EG is the diameter of the circle
∴ The center of the circle is the mid-point of EG
∵ The mid-point of EG is 
∴ The center of the circle is (6 , 3)
