Answer:
32/4= 8 (there is a factor of 8 between x and y at all times)
128/8 = 16 (divide y by 8 to find out what x is.
x= 16 when y= 128
Step-by-step explanation:
Since the smaller one is 1/2 the size (as shown in the measurement on the bottom) I would divide the other area by 2 as well, so the answer is 12 I believe
1 = 4 quarters
2 = 8 quarters
3 = 12 quarters
4 = 16 quarters
5 = 20 quarters
6 = 24 quarters
7 = 28 quarters
ooops. too much
6 and 3/4 = 27 quarters
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above
![y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=y%20%3D%20%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B1%7D%7B3%7D%7Dx%2B5%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)
