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4 years ago

Two planes intersect in a ? point, line,line segment, or ray

Mathematics

1 answer:

denis-greek [22]4 years ago

6 0

Two planes intersect at a Line.

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Rob has a dog that weighs 3 times as much as ricks dog the total weight of both dogs is 76 pounds how much does robs dog weigh d

rewona [7]

76 / 4 = 19

19 * 3 = 57

Rob's dog is 57 pounds.

Rick's dog is 19 pounds.

6 0

3 years ago

Please helpp me what is a & b explain thinking!!!

ankoles [38]

A=4 B=3 4+3=7 there are 4 squares 7x4=28 which is the full length. Hope this helps

8 0

3 years ago

Read 2 more answers

Please Awnser as soon as possiable

Cerrena [4.2K]

Answer:

GH and GI

Step-by-step explanation:

Yeah

5 0

2 years ago

How do you know the number of part to divide a number line from 0 to 1 into when comparing fractions

Katyanochek1 [597]

To compare fractions you need a common denominator, then you can make a comparison. You would divide the number line between 0 and 1 (or any 2 whole numbers on the number line) based on that common denominator. For example... if you were trying to compare 3/4 and 2/8, you would find the common denominator (in this case 8) and convert the fractions...

3/4 = 6/8
2/8 stays as 2/8

Now you would go to the number line between 0 and 1 and divide it into 8 equal pieces. 3/4 would go over the 6th division and 2/8 would go over the second division.

That would give you a good visual that 2/8 < 3/4

[ / / / / / / / ]

0 2/8 3/4 1

4 0

4 years ago

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

victus00 [196]

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials : n= 4

Now, the required probability will be :

$P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401$

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

5 0

3 years ago