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4 years ago

Two planes intersect in a ? point, line,line segment, or ray

Mathematics

1 answer:

denis-greek [22]4 years ago

6 0

Two planes intersect at a Line.

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I need help with a math question but apparently everyone is dead today..

Gwar [14]

The answer is D. I’m assuming this is surface area so here’s my explanation:) ok so the area of the triangle is 6 (4x3 divided by 2) and when you add the other triangle that’s 12. Ok so we have 12 so far. Then the area of the bottom rectangle is 24 (3x8). Then the area of the side rectangle is 32 (4x8). THEN the top rectangle’s area is 40 (8x5). When you add the numbers up (12+24+32+40) you get 108! And of course dont forget the cm2. ( centimeters squared ). :) I hope this helps

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3 years ago

Three ballet dancers are positioned on stage. Wanda is straight behind Simon and directly left of Jaylen. If Simon and Wanda are

leonid [27]

Answer:

Step-by-step explanation:

Draw a picture. You have a right triangle with hypotenuse = 5 and one leg = 4.

length of remaining leg = √(5²-4²) = 3 ft

5 0

3 years ago

Read 2 more answers

Max's car holds 18 gallons of gasoline. Driving on the highway, the car uses approximately 2 gallons per hour. Let h represent t

Mice21 [21]

Y= 18 gallons-2(h)
y is what you're trying to find out and since there are 18 gallons in the tank after every hour you would have 2 less gallons. So, you can multiply how many hours he's been driving by the 2 gallons and subtract it from 18

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3 years ago

which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}

Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

$A+B>C\\A+C>B\\B+C>A$

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

$6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}$

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

$5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}$

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

$4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}$

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

$2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}$

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

5 0

3 years ago

Read 2 more answers

An airplane ascends from the ground at an angle

Evgen [1.6K]

The answer is 190 as it’s sin17 =x/650

4 0

2 years ago