Answer:
Option C. 
Step-by-step explanation:
we know that
![A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BP%5B%281%2Br%29%5E%7Bn%7D%20-1%5D%7D%7Br%281%2Br%29%5E%7Bn%7D%7D)
we have



substitute in the formula
![A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B400%5B%281%2B0.00625%29%5E%7B72%7D%20-1%5D%7D%7B0.00625%281%2B0.00625%29%5E%7B72%7D%7D%5C%5C%20%5C%5CA%3D%5Cfrac%7B226.446972%7D%7B0.009788%7D%5C%5C%20%5C%5CA%3D%5C%2423%2C134.61)
Answer:
$0.37 and $0.31
Step-by-step explanation:
Well, you already found the answer :)
x = average of next 5 quizzes
4 * 73 = first 4 quizzes
There will be a total of 4 +5 = 9 quizzes
Average of all quizzes = 88 = (4*73+5x)/9
9*88 = 9*(292 +5x)/9
792 = 292 + 5x
500 = 5x
X = 500/5 = 100
<span> Next 5 quizzes need
to average 100</span>