Andre Roberts scored a total of 34 touchdowns
An equation is an expression that shows the relationship between two or more variables and numbers.
The total touchdowns is 80.
Duke Johnson scored 14 of the touchdowns.
Josh McCown scored 40% of the touchdowns. = 40% of 80 = 0.4 * 80 = 32
Let x represent the number of touchdowns scored by Andre Roberts, hence:
x + 14 + 32 = 80
x + 46 = 80
x = 34
Andre Roberts scored a total of 34 touchdowns
Find more about equation at: brainly.com/question/2972832
Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3
Side 2 and side 3 are the longer two congruent sides
Add up the three sides and set them equal to the given perimeter of 33. Solve for x
(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5
If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)
Answer: 13 inches
Answer:
34%
Step-by-step explanation:
To find what percent a part is of the whole, divide the part by the whole and multiply by 100%.

Answer:
(a) 169.1 m
Step-by-step explanation:
The diagram shows you the distance (x) will be shorter than 170 m, but almost that length. The only reasonable answer choice is ...
169.1 m
__
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
The leg of the right triangle adjacent to the marked angle is x, and the hypotenuse is 170 m. Putting these values into the equation, you have ...
cos(6°) = x/(170 m)
x = (170 m)cos(6°) ≈ (170 m)(0.994522) ≈ 169.069 m
The horizontal distance covered is about 169.1 meters.
_____
<em>Additional comment</em>
Expressed as a percentage, the slope of this hill is tan(6°) ≈ 10.5%. It would be considered to be a pretty steep hill for driving.
Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.
La pendiente de una reta es la <u>razón entre el cambio vertical y el cambio horizontal,</u> o sea, cual el cambio vertical cuando el cambio horizontal es de 1.
En este problema, hay que:
- La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
- Bajado 1000 pies, entonces, aplicando la proporción:
1 pie H -> -100 pies V
x pie H -> -1000 pies V
Aplicando la multiplicación cruzada:




El cambio en la distancia horizontal es de 10 pies.
Un problema similar es dado en brainly.com/question/24766917