Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Slope is rise/run
so, you go up 4 times and run across 3 times, this is a positive slope, so the slope is
slope: 4/3
the y-intercept is the line that passes the y-axis, (0, -5),
y-intercept: -5
put it together
4/3x-5
The GCF of the equation would be 5x^2.
Answer:
I think the other one is right
Step-by-step explanation:
