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3 years ago

What is the LCDof two numbers if one number is a multiple of the other give an example

Mathematics

1 answer:

mylen [45]3 years ago

7 0

What's the choices to the question

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Simplify ( 5 1/3) to the 3rd power

Alborosie

Answer: 125 /3

Step-by-step explanation:

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3 years ago

A circular track has a diameter of 62 yards, whats the circumference of the track

earnstyle [38]

Answer:

194.78 yards

Step-by-step explanation:

Diameter: d=62yards

Perimeter: p=2×pi×r=pi×d, where d=2×r, r being the radius.

We get: p=pi×d=62×pi=194.78 yards

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4 years ago

1. Simplify 3(2x + 5) 6x + 30 0 6x +15 16x + 5

inysia [295]

Answer:

6x+15

Step-by-step explanation:

3×2x + 3×5. use the distributive property of multiplication

4 0

3 years ago

Raghav, Rajit, Junsu, Mia, and Umema were finished with lunch and began playing with drink straws. Each one was making a line de

vodomira [7]

Answer:

x = $25.8^{o}$ and y = $51.4^{o}$

Step-by-step explanation:

Known that he sum of angles on a straight line is $180^{o}$ . From the diagram;

2y + x + y = $180^{o}$

x + 3y = $180^{o}$ ................ 1

Also,

2x + x + 2y = $180^{o}$

3x + 2y = $180^{o}$ .............. 2

Using the elimination method, multiply equation 1 by 3 and equation 2 by 1

3x + 9y = 540 ............ 3

3x + 2y = $180^{o}$ ............. 4

7y = 360

y = $\frac{360}{7}$

y = $51.4^{o}$

substitute the value of y in equation 1,

x + 3y = $180^{o}$

x + 3(51.4) = $180^{o}$

x + 154.2 = $180^{o}$

x = $180^{o}$ - 154.2

x = $25.8^{o}$

Thus, x = $25.8^{o}$ and y = $51.4^{o}$

6 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago