I believe they are: (2,8), (4,6), (1,7), and (3,5) I could be wrong, but I'm almost certain that's it. Hope that helps.
1. x - 4
x - 6|x² - 10x + 24
- (x² - 6x)
-4x + 24
- (4x + 24)
0
The answer is C.
2. A. 9x² + 12x - 3
3(x²) + 3(4x) - 3(1)
3(x² + 4x - 1)
B. 9x² + 3x - 5
Not Factored
C. 6x² + 10x - 4
2(3x²) + 2(5x) - 2(2)
2(3x² + 5x - 2)
2(3x² + 6x - x - 2)
2(3x(x) + 3x(2) - 1(x) - 1(2))
2(3x(x + 2) - 1(x + 2))
2(3x - 1)(x + 2)
D. 6x² + 7x - 6
Not Factored
The answer is C.
3. 3x³ - 4x² + 3x - 6
x + 2|3x⁴ + 2x³ - 5x² + 0x - 4
- (3x⁴ + 6x³)
-4x³ - 5x²
- (-4x³ - 8x²)
3x² + 0x
- (3x² + 6x)
-6x - 4
- (-6x - 12)
8
The answer is A.
Answer:
b=2.5
p=6
Step-by-step explanation:
Take the fraction and simplify it. So 10/8 would be 5/4
You multiply the 2 by 2, giving you h/4
So now you have 5/4=h/4
h=5 but now you have to divide both by 2 again so it can go back to the original fraction.
5÷2=2.5 and 4÷2=2
Second Problem! 4/2 is equal to 2/1
You can also multiply 4 by 3 to get the numerator as 12. Multiply the 4 by 3 and the 2 by 3
Now you have 12/6= 12/p
So p is 6
Step-by-step explanation:
You want to set one of the equations equal to either x or y. For this, I put x+y=-2 equal to y which would be y=-x-2. Then you plug this in to the other equation for y. This would give you 5x+2(-x-2)=2. When you factor the two into the parenthesis, combine like terms, and keep the x values on ones side and the other numbers on the other side, you get 3x=6
Answer:
a. y = 3 × 0 + 15
y= 0+15
y= 15
Step-by-step explanation:
Subtitute the variables into the place they are denoted with and solve it
And the place where the equation will cross the y axis is just the last numbers i.e. 15 and 3z which is 6
