All categories

3 years ago

What is the area of the Rhombus

Mathematics

1 answer:

Andrews [41]3 years ago

4 0

The answer is 176. The second answer choice. It’s because if you have a four below the to four you would get 8 and 11 plus 11 would give you 22 so 8x22 gives you 176!

You might be interested in

8x – 65 = - x2 [pease help me

Leya [2.2K]

Answer: x=5 or x=−13

Step-by-step explanation:

8x−65=−x2

8x−65−(−x2)=−x2−(−x2)

x2+8x−65=0

(x−5)(x+13)=0

x−5=0 or x+13=0

x=5 or x=−13

4 0

3 years ago

What expression is equivalent to (x+9)(x-2)-9x-6

Elden [556K]

Answer:

x(to the 3rd power) +7x(to the 2nd power) − 27x − 6

Step-by-step explanation

3 0

3 years ago

How do I find the integral ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?

defon

$\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1$

$(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1$

$\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2$

$\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3$

$\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}$

4 0

3 years ago

The range of the function? 1 2 2 4 3 9 4 16

wariber [46]

Answer:

2,4,9,16

Step-by-step explanation:

are range because they are exactly opposite of domain

6 0

2 years ago

Please help i dont know how to do this

sveticcg [70]

Answer:

Step-by-step explanation:

jason is filling up a 3/4 gallon pitcher. the one he has to fill it up with is 1/3 of a gallon.

1/3 * x = 3/4

x/3 = 3/4

3 (x/3) = 3 (3/4)

3x/3 = 9/4

x = 9/4

9/4 is 2.25 so the answer is B

6 0

3 years ago

What is the area of the Rhombus​

What is the area of the Rhombus