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3 years ago

Multiply or divide as indicated. 20b²c³/4bc

Mathematics

2 answers:

STALIN [3.7K]3 years ago

4 0

We can separate this into three parts.

20/4 = 5
B^2/b= b
C^3/c = c^2

Therefore, the answer is 5bc^2

Anastasy [175]3 years ago

4 0

Answer:

Step-by-step explanation:

$\dfrac{20b^2c^3}{4bc}=\left(\dfrac{20}{4}\right)\left(\dfrac{b^2}{b}\right)\left(\dfrac{c^3}{c}\right)\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\ \text{and}\ a=a^1\\\\=5b^{2-1}c^{3-1}=5bc^2$

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Software - Infinite Algebra 2 Absolute Value Inequalities Solve each inequality and graph its solution. Name Sarmant Date 3/8/20

gulaghasi [49]

$|6+9x|\le24$

this is the correct way to solve these types of exercises

then we will try to do the same where a is (6+9x) and b is 24

$|6+9x|\le24\longrightarrow-24\le6+9x\le24$

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$\begin{gathered} -24-6\le6-6+9x\le24-6 \\ -30\le9x\le18 \end{gathered}$

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11 months ago

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3 years ago

Find the distance between the points L(7,-1) and M(-2, 4).

zysi [14]

Answer:

The answer is

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

$|LM| = \sqrt{ ({7 + 2})^{2} + ( { - 1 - 4})^{2} } \\ = \sqrt{ {9}^{2} + ({ - 5})^{2} } \\ = \sqrt{81 + 25} \\ = \sqrt{106} \: \: \: \: \: \: \: \\ = 10.29563014...$

We have the final answer as

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Hope this helps you

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2 years ago