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Montano1993 [528]
3 years ago
7

graph each system of equations as a pair of lines in the xy-plane. Solve each system and interpret your answer. 19. x - y = 1 -

2x + 2y = 5

Mathematics
1 answer:
barxatty [35]3 years ago
4 0
<h2>Answer with explanation:</h2>

The given system of equations :

x - y = 1-------(1)\\\\-2x + 2y = 5-------(2)

To plot the given equations of xy plane, we first consider equation (1)

x - y = 1

Now, we put some random values of x and note the y values on them

At x= 0  , 0 - y = 1\Rightarrow\ y=-1

At x= 1  , 1 - y = 1\Rightarrow\ y=1-1=0

i.e. points to plot equation (1) = (0,-1) and (1,0).

Now, consider equation (2),

At x= 0  , - 2(0)+ 2y = 5\Rightarrow\ y=\dfrac{5}{2}=2.5

At x= 1  , -2(1)+2 y = 5\Rightarrow\ 2y=5+2\Rightarrow\ y=\dfrac{7}{2}=3.5

i.e. points to plot equation (2) = (0,2.5) and (1,3.5).

Now, we plot the equation as given below, we can see that the lines are parallel lines , also the parallel lines has no intersecting point, it means it has NO SOLUTION.

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4

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2 years ago
Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline
yawa3891 [41]

Answer:

B) 4.07

Step-by-step explanation:

First we need to calculate the mean of all the data, which is the same as the mean of the means of each grade of gasoline:

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39.31             36.69                38.99             40.04

39.87            40.00                40.02             39.89

39.87            41.01                  39.99             39.93

X1⁻=39.68    X2⁻= 39.23       X3⁻= 39.66    X4⁻=  39.95

Xgrand⁻ = (39.68+39.23+39.66+39.95)/4 = 39.63

Next we need to calculate the sum of squares within the group (SSW) and the sum of squares between the groups (SSB), and the respective degrees of freedom):

SSW = [ (39.31-39.68)² + (39.87-39.68)² + (39.87-39.68)² ] + [ (36.69-39.23)² + (40.00-39.23)² + (41.01-39.23)² ] + [ (38.99-39.66)² + (40.02-39.66)² + (39.99-39.66)² ] + [ (40.04-39.95)² + (39.89-39.95)² + (39.93-39.95)² ] = [0.2091] + [10.2129] + [0.6874] + [0.0121] = 11.12

SSW =  11.12

Degrees of freedom in this case is calculated by m(n-1), with m being the number of grades of gasoline (4) and n being the number of trial results for each one (3), so we would have 4(3-1) = 8 degrees of freedom

SSB = [ (39.68-39.63)² + (39.68-39.63)² + (39.68-39.63)²] + [ (39.23-39.63)² + (39.23-39.63)² + (39.23-39.63)² ] + [ (39.66-39.63)² + (39.66-39.63)² + (39.66-39.63)² ] + [ (39.95-39.63)² + (39.95-39.63)² +(39.95-39.63)² ] = [0.0075] + [0.48] + [0.0027] + [0.3072] = 0.7974

SSB =  0.80

For this case, the degrees of freedom are m-1, so we would have 4-1 = 3 degrees of freedom

Now we can establish the hypothesis for the test:

H0: μ1 = μ2 = μ3 = μ4

The null hypothesis states that the means of miles per gallon for each fuel are the same, indicating that the drade of gasoline does not make a difference, therefore our alternative hypothesis will be:

H1: the grade of gasoline does makes a difference

We will use the F statistic to test the hypothesis, which is calculated like follows:

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We know that the level of significance we are using is α = 0.05, so to find the critical value F we need to look at some table of critical values for the F distribution for the 0.05 significance level (like the attached image). Then we just need to look fot the value that is located in the intersection between the degrees of freedom we have in the numerator (horizontal) and the denominator (vertical) of the statistic (3 and 8). That critical value is:

Fc = 4.07

3 0
3 years ago
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-2Step-by-step explanation:

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