D, it is term number 4....
Answer:
t_a = 7 s
t_w = 5 s
Step-by-step explanation:
Given:
- The average speed in air v_a = 16 m/s
- The average speed in water v_w = 3 m/s
- The total distance D = 127 m
- The total time T = 12 s
Find:
How long did the stone fall in air and how long did it fall in the water?
Solution:
- Lets time taken by stone to drop through air as t_a = t_a.
- The time taken in water would be t_w = (12 - t_a)
- The total distance covered can be calculated as:
D = v_a*t_a+ v_w*(12 - t_a)
127 = 16*t_a + 3*(12 - t_a)
Simplify and solve for t:
91 = 16*t_a - 3t_a
13*t_a = 91
t_a = 7 s
t_w = 5 s
Answer:
B. (2,8), because both equations intersect at this point
Answer:
Step-by-step explanation:
Subtract 9 from both sides:
Add 6x to both sides:
Divide both sides by -4:
Answer:
17
Step-by-step explanation:
54 has 4 ones
and 5 tens
37 has 7 ones
and 3 tens
subtracting ones
7 ones are taken from 54
so along with the existing 4, 1 ten is decreased and another 3 ones are decreased resulting in 7 ones now
now 54 has 5-1= 4 tens
subtracting tens we get 4-3=1
Therefore 1 ten and 7 ones
⇒ 17
