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Cloud [144]
2 years ago
12

Generate a plan and describe the steps needed to solve the equation. 34 = –(m + 3)

Mathematics
1 answer:
djyliett [7]2 years ago
4 0

Answer: If you are solving for m it would be -37 or 37 with the added negative

Step-by-step explanation:

34 = -(m + 3)

34 = -m - 3

+ 3 = -m + 3

37 = -m

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2x + 3 = 5 x = plz answer thank you
posledela

x=1

explaination:

2x+3=5x

Subtract 5x from both sides.

2x+3−5x=0

Combine 2x and −5x to get −3x.

−3x+3=0

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

−3x=−3

Divide both sides by −3.

x=  

−3

−3

​

 

Divide −3 by −3 to get 1.

x=1

8 0
2 years ago
Read 2 more answers
Suppose that g(x) varies inversely with (x) and g(x) = 0.2 when x=0.1. What is g(x) when x=1.6?
mestny [16]
Since g(x) varies with x, therefore:
g(x) = k/x where k is a constant.

So, first we need to get k. We are given that g(x) = 0.2 when x = 0.1
Substitute with these values to get k as follows:
g(x) = k/x
0.2 = k/0.1
k = 0.2*0.1 = 0.02

Now, the equation became:
g(x) = 0.02 / x

We need to get the g(x) when x = 1.6
Therefore, we will substitute with x in the equation and calculate the corresponding g as follows:
g(x) = 0.02 / 1.6
g(x) = 0.0125
6 0
2 years ago
Read 2 more answers
which of the following plotted points on the graph represent the zeros of the function g(x) = (x^2 - 3x - 10)(x + 4)
Natalka [10]

Answer: The answer would be (-2,0),(-4,0), and (5,0)

Step-by-step explanation:

Guessing the answer choices are

(-2,0)

(4,0)

(0,10)

(-4,0)

(0,-2)

(0,-10)

(5,0)

3 0
2 years ago
Twice a number, decreased by 9 is 12
Serhud [2]

Answer:

10.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle
Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

  • \sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.
  • \tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.

8 0
3 years ago
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