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Elza [17]
2 years ago
5

11. A surveyor is 100 meters from a bridge. The angle of elevation to the top of the bridge is 35º. The

Mathematics
1 answer:
Anna [14]2 years ago
6 0

Answer:

The height of the bridge is 71.47 m.

Step-by-step explanation:

Since the eye of the surveyor is 1.45m creating the horizontal distance, we must add the 1.45 m to the 70.02 m to determine the total height of the bridge.

70.02 m + 1.45 m = 71.47 m

The height of the bridge is 71.47 m.

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5 times a number is 110 less than 7 times that number
Nitella [24]

Answer:

55

Step-by-step explanation:

let the number=x

5x=7x-110

7x-5x=110

2x=110

x=110/2=55

3 0
3 years ago
Can someone help please?
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2 years ago
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ElenaW [278]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
Student incorrectly claims that 2/3÷5/9 = 5/6 find the correct quotient what was the students error
olga_2 [115]

Answer:

6/5

Step-by-step explanation:

2/3 ÷ 5/9

2/3 × 9/5 ( while changing division to multiple, numerator and denominator changes

2 × 3/5 ( 9/3 =3

Ans =6/5

6 0
2 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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