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Alik [6]
3 years ago
11

I need the answer please

Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Nike Super Sale $$$ (Additional Instructions in Photo) !!25 POINTS!!
mr Goodwill [35]

The markup percentage regarding the sale of the good will be 136%.

<h3>How to calculate the percentage?</h3>

From the information given, the initial cost is $55.00 and the new price is $130.19. The increase in percentage will be:

= (130.19 - 55)/55 × 100

= 75.19/55 × 100

= 136%

Therefore, the markup percentage regarding the sale of the good will be 136%.

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5 0
2 years ago
Which angles are alternate exterior angles?
omeli [17]
A. 2 and 8
It’s the pair of angles on the outer side of each of those two lines but on opposite of the transversal.
4 0
3 years ago
Help I need to get this done I have 15 questions
ivanzaharov [21]

Answer:

8 cm

Step-by-step explanation:

(See the image attached for details)

  • The blue segment measures 15 cm
  • The green segment measures 7 cm
  • The green and yellow segment when added form the blue segment
  • So: ? + 7 = 15

Solve:

? + 7 = 15

Subtract 7 on both sides:

? + 7 = 15

   -7     -7

? = 8 cm

Therefore, the yellow segment, or the missing side length, measures 8 cm.

4 0
3 years ago
HELP IVE BEEN STRUGGLING FOR THE PAST 15 MIN PLEASEEEEE
joja [24]

<u>Answer:</u>

c=  -1/2

<u>Step-by-step explanation:</u>

Let's solve your equation step-by-step.

4 /3  = −6c − 5/ 3

Step 1: Simplify both sides of the equation.

4 /3  =−6c +  −5 /3

Step 2: Flip the equation.

−6c +  −5 /3  =  4/3

Step 3: Add 5/3 to both sides.

−6c +  −5 /3  +  5 /3  = 4/3  +  5 /3  −6c

=3

Step 4: Divide both sides by -6.

−6c  −6   =  3 − 6 c =  −1 /2

4 0
4 years ago
Read 2 more answers
If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

so that

\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34

So we end up with

\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}

###

Another way to do this:

\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}

\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
3 years ago
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