(0,0) and (-4,-5) in point slope form (please show work if possible)
2 answers:
Givens:
point slope form: y-y1=m(x-x1)
need to find slope "m"
x1=0, y1=0, x2=-4, y2=-5
m= (y2-y1)/ (x2-x1)= (-5-0)/(-4-0)= -5/-4=5/4
than just substitute for either point
y-0=5/4(x-0)
or
y+5=5/4(x+4)
I think formula is y2-y1 divided by x2-x1 so if im correct
-5/-4
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In slope intercept form this would just be: y=-3
SOH CAH TOA
Cosine is adjacent over hypotenuse so you're answer is C.
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