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White raven [17]
3 years ago
10

(08.02 LC) The dot plots below show the weights of the players of two teams: Two dot plots are shown one below the other. The to

p and the bottom plots have the title Team C and Team D respectively. Below the line for each dot plot is written Weight followed by pounds in parentheses. The markings on each line are from 120 till 140 at intervals of 1. For the top plot there are 2 dots each for 130 and 139 and 1 dot each for 126, 127, 132, and 135. For the bottom plot there are two dots each for 120, 121 and 126 and 1 dot each for 123, and 128. Based on visual inspection of the dot plots, which team appears to have the larger mean weight?
Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

It would be much easier to answer of there was some diagram or something but if there is only just Team C and D then, it would be Team D

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X/10.24=4 tell me what is the answer?
denpristay [2]

Answer:

40.96

Step-by-step explanation:

x/10.24=4

times 10.24 on both sides

10.24 times 4

x=40.96

7 0
2 years ago
lemont has 30 books to pack the boxes each box holds 7 books if he fills each box how many boxes are left over
mariarad [96]

Answer:

2 books

Step-by-step explanation:

If 7 books= 1 box

Then 30 books= 30÷7= 4 boxes with a remainder of 2 books

Therefore books left over= 2 books

6 0
2 years ago
2ND QUESTION. PLEASE PLEASE HELP. 20 POINTS!!!!!!!!ANSWER IN FUL SENTENCES
kupik [55]

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i dont know what it means but the right image is 4 times larger than the left image

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6 0
2 years ago
6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally dis
Yakvenalex [24]

Answer:

92.9997<\mu<99.5203

Step-by-step explanation:

Using the formula for calculating the confidence interval expressed as:

CI = xbar ± Z * S/√n where;

xbar is the sample mean

Z is the z-score at 90% confidence interval

S is the sample standard deviation

n is the sample size

Given parameters

xbar = 96.52

Z at 90% CI = 1.645

S = 10.70.

n = 25

Required

90% confidence interval for the population mean using the sample data.

Substituting the given parameters into the formula, we will have;

CI = 96.52 ± (1.645 * 10.70/√25)

CI = 96.52 ± (1.645 * 10.70/5)

CI = 96.52 ± (1.645 * 2.14)

CI = 96.52 ± (3.5203)

CI = (96.52-3.5203, 96.52+3.5203)

CI = (92.9997, 99.5203)

<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em>\mu<em><99.5203</em>

4 0
2 years ago
Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0
3 years ago
Read 2 more answers
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