Answer:
Month 8
In this month Company B's plan will pay $64,000 versus $45,000 from Company A.
Step-by-step explanation:
Start by calculating the monthly payments for both plans.
Month - Company A - Company B
1 $10,000 $500
2 $15,000 $1,000
3 $20,000 $2,000
4 $25,000 $4,000
5 $30,000 $8,000
6 $35,000 $16,000
7 $40,000 $32,000
8 $45,000 $64,000
9 $50,000 $128,000
10 $55,000 $256,000
11 $60,000 $512,000
12 $65,000 $1,024,000
13 $70,000 $2,048,000
14 $75,000 $4,096,000
15 $80,000 $8,192,000
16 $85,000 $16,384,000
17 $90,000 $32,768,000
18 $95,000 $65,536,000
19 $100,000 $131,072,000
20 $105,000 $262,144,000
21 $110,000 $524,288,000
22 $115,000 $1,048,576,000
23 $120,000 $2,097,152,000
24 $125,000 $4,194,304,000
Answer:
i dont remember how to do this and i just did this last year
Step-by-step explanation:
Step-by-step explanation:
I think the answer is 3x square multiplied by 1
Coz anything raised to power 0 will always equal to 1
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5