Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
0.08x+(x-200)
(0.08x)(x+-200)
(0.08x)(x)(0.08x)(-200)
= 0.08x^2-16x
Answer:
Step-by-step explanation:
z = 119 Vertically opposite angles are equal.
5x + 41 + 119 = 180 5x + 41 and 119 are supplementary.
4x + 160 = 180 Subtract 160 from both sides
4x = 180 - 160
4x = 20 Divide by 4
x = 20/4
x = 5
9a-5x
step by step explanation:
you can only add and subtract numbers that have the same variables.
12a and 3a are related because there variable is both a.
when u subtract 12a-3a you get the answer of 9a using subtraction.
7x and -2x are the second pair of related terms because they also have the same variable (x)
7x-2x is 5x using subtraction.
put the expression together:
9a-5x
hope this helps!
give me brainliest if it did plz
