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Mademuasel [1]
3 years ago
13

Which graph is represented by the graph below

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
I believe its the second one y=1/2e^x im sorry if im wrong
You might be interested in
A
Serjik [45]

Answer

925 students brought their lunch.

Explanation

First let's rewrite the equation.

You know that "of" means multiply and "is" means equal.

Okay, so let's break it down.

The question says, "At your school, 74% of students brought their lunch at the cafeteria. There are 1250 students in the school."

This means that 74% of 1250 students brought their lunch at the cafeteria.

You are trying to find how many students brought their lunch. This will be x.

So the equation would be this.

74% × 1250 = x

74% is 0.74.

0.74 × 1250 = x

0.74 × 1250 = 925

So 925 students brought their lunch.

6 0
3 years ago
Answer ASAP<br><br> Find the area
slavikrds [6]

In this problem, you are asked to find the area of the trapezoid. The formula in finding the area of the trapezoid is:

A = [(a + b)/2] x h

Where a = base 1

             b = base 2

             h = height

Substituting the given measurements to the formula:

A = [(1.7 m + 6.7 m) / 2] x 5 m

A = (8.4 m / 2) x 5 m

A = 4.2 m x 5 m

A = 21 m^2

Therefore, the area of the trapezoid is 21 square meters.

3 0
3 years ago
PLEASE HELP URGENT!!!!!!!! NUMBER 46 AND 47!!!!!!!!!!!!!!
crimeas [40]

Answer:

46 is d I'm not sure for 47 but I think it's c not sure tho

7 0
3 years ago
Murat has 2/3 kg of rice that he wants to put into bags that contain 3/10 kg of rice each?
Bad White [126]

Answer:

Murat can fill 6/13 kg of rice

Step-by-step explanation:

because it has 2/3 kg of rice and 3/10 each and I added 6+2 and 3+10 hope it makes your day

8 0
2 years ago
Read 2 more answers
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
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