Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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They are not equivalent.
24/6= 4,
4/2=2
6/24= 0.25,
0.25/2= 0.125
2 does not equal 0.125
Final answer: Not equivalent
To solve, we need to subtract from these two fractions. In order to do this, we will change one of them to have the same denominator as the other.
We have 5/14 and 1/7
Let us change 1/7
Multiply 2/2 (a form of 1 so it does not change the value of the fraction)
2/2 • 1/7 = 2/14
Now subtract from 5/14
5/14 - 2/14 = 3/14
ANSWER: Vicky ran 3/14 of a mile more
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