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denis23 [38]
3 years ago
8

What are the standard measurement sizes for dry measuring cups?

Mathematics
1 answer:
swat323 years ago
7 0

Answer:

The standard 4 measuring cup sizes are: 1 cup, 1/2 cup, 1/3 cup and 1/4 cup. With those four cup sizes you can measure dry ingredients for any recipe.

Step-by-step explanation:

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What is the length of a rectangle with an area of 48 yd squared, and a width of 3 yd
Leona [35]
The length of the rectangle is 16.
7 0
3 years ago
Read 2 more answers
These figures are similar: angle R = ?
lesya692 [45]
It’s similar to D because they are going to have the same measured angle
5 0
3 years ago
a rectangular garden is fenced on alls ides with 256 feet fencing. the garden is 8 feet longer than it is wide
pickupchik [31]

The length and width of the rectangular garden is estimated as-

  • Length = 68 ft
  • width= 60 ft
<h3>How to calculate perimeter of the rectangle?</h3>

A rectangle's perimeter is the total length and distance of its border across all sides. The perimeter of a rectangular box is a linear measurement that is expressed in meters, feet, cm, or yards. Let us first examine the two primary characteristics of a rectangle.

  • A rectangle's four angles are all 90°.
  • A rectangle's opposite sides are of equal length.

The perimeter of the rectangle is given as-

Perimeter = 2(length + width)

perimeter= 256

Let the width of the rectangle be x.

Length is 8 feet longer than width, Thus,

length = x+8

Substitute the values in the formula of perimeter;

256 = 2( x+ 8+ x)

256 = 2( 2x + 8)

128= 2x + 8

120= 2x

x=60

Thus, width = 60 ft.

Length = 60 + 8 = 68 ft.

Therefore, the length and width of the rectangular garden is estimated.

To know more about the area of the rectangle, here

brainly.com/question/2607596

#SPJ4

The complete question is -

A rectangular garden is fenced on all sides with 256 feet of fencing. The garden is 8feet longer than it is wide. Find the length and width of the garden.

6 0
2 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

4 0
3 years ago
Read 2 more answers
Double the product of 4y and 3b if y=2 and b=1.
Aleksandr-060686 [28]

Answer:

48

Step-by-step explanation:

Double the product of 4y and 3b

2 * ((4y) * (3b))

y = 2 and b = 1

2 * ((4 * 2) * (3 * 1))

2 * (8 * 3)

2 * 24

48

3 0
3 years ago
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