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MAXImum [283]
3 years ago
13

Lilly estimated a quotient of 120 and found an actual quotient of 83. what should she do next?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0
She should explain how she got 83 and maybe why she guessed 120 before
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Eden has a part time job. She gets paid £7. 20 per hourthis week she worked for 18 1/2 hourswork out Eden's total pay for this w
Dafna1 [17]

Answer:

$133.20

Step-by-step explanation:

Since the amount of hours she worked isn't a whole number, we can first separate 18 and 1/2 and work the problem out one at a time.

1. Multiply 7.20 by 18 to get 129.60

2. Multiply 0.50 by 7.20 to get 3.60.

3. Add 129.60 and 3.60 together to get the answer, 133.20.

5 0
2 years ago
The table below represents an exponential function what is the common ratio
Greeley [361]

Solution:

Given:

A table representing an exponential function.

The x-values represent the terms, while the y-values represent the numbers.

The common ratio is gotten from the numbers (y-values).

The formula for common ratio is given by;

\begin{gathered} r=\frac{present\text{ term}}{preceed\text{ ing term}} \\  \\ \text{Hence,} \\ r=\frac{108}{36}=\frac{36}{12}=\frac{12}{4}=\frac{4}{1.33\ldots}=\frac{1.33\ldots.}{0.44\ldots} \\ r=3 \end{gathered}

Therefore, the common ratio is 3.

3 0
1 year ago
Given ∠8≅∠12 .
Serggg [28]
Your answer would be B
When you have two angles, and want to know which lines must be congruent, you have to look at the transversal first. The two angles will share a side which is the transversal, and then their other side is one of the parallel lines. 
The converse of the corresponding angles theorem states that If corresponding angles are congruent, then the lines are parallel.
7 0
3 years ago
Read 2 more answers
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Question 4 (1 point)
igomit [66]

Answer:

x = 15

Step-by-step explanation:

We want to solve for x in  3*(2x + 5) = 3x + 4x

First simplify.

3*(2x + 5) = 7x

Next, distribute the 3.

3*2x + 3*5 = 7x

6x + 15 = 7x

15 = 7x - 6x

15 = x

4 0
3 years ago
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