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3 years ago

Please help me!!!!!!!!!

Mathematics

1 answer:

Serga [27]3 years ago

5 0

Answer:

Step-by-step explanation:

I assume we are finding the slope of the line. It is positive since it runs from the lower left to the upper right, so forget B and D. Since slope is defined as rise over run, in order to get from one point on the line that goes through right where the grids meet to another point that goes through right where the grids meet we count up 1 unit and then to the right 6 units. This is a slope of 1/6.

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I have no clue what to do... please help

strojnjashka [21]

Answer:

Multiply the base by the exponent

Step-by-step explanation:

7 0

3 years ago

Where does the graph of y=2x2-x-3 cross as the x-axis?

tiny-mole [99]

This can be determined by finding the x-intercept. In doing so, we let y=0 to find the value of x.

y= 2x^2 -x -3
[0 = 2x^2 -x-3]÷2
0 = x^2 -1/2 x - 3/2

Complete the squares:

1/16 + 3/2 = x^2 - 1/2x + 1/16
25/16 = (x -1/4)^2
sqrt (25/16) = x - 1/4
+/- 5/4 = x - 1/4

Thus,
x = 1/4 + 5/4 = 3/2
x = 1/4 - 5/4 = -1

Thus, the graph crosses at x = 3/2 and x = -1.

6 0

3 years ago

WILL MARK YOU BRAINLIEST

slega [8]

Answer:

i need more details then this its not really explaining anything

Step-by-step explanation:

5 0

3 years ago

What is the reason that absolute value is always written as a positive?

trapecia [35]

Answer:

Absolute value is talking about distance (Distance from zero); distance is always measured by positive numbers.

5 0

3 years ago

The notation Ak meas the matrix A Multiplied with itself k times (a) For the 2×2 identity matrix I, show that I2 =I (b)For the n

djverab [1.8K]

Answer:

Entries of I^k are are also identity elements.

Step-by-step explanation:

a) For the 2×2 identity matrix I, show that I² =I

$I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

Hence proved I² =I

b) For the n×n identity matrix I, show that I² =I

n×n identity matrix is as shown in figure

Elements of identity matrix are

$\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\$

As square of 1 is equal to 1 so for n×n identity matrix I, I² =I

As mentioned above

$\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\$

Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I

6 0

3 years ago