Question

Which equation has the solutions x=-3 -+ square root of 3i/2?

Answer 1

A. 

You can get this by using the quadratic function. 

Answer 2

Answer:

$x^2+3x+3=0$

Step-by-step explanation:

Given : $x=\frac{-3 \pm \sqrt{3}i}{2}$

To Find :Which equation has the solutions $x=\frac{-3 \pm \sqrt{3}i}{2}$

Solution:

$\frac{x-3 - \sqrt{3i}}{2} \times \frac{x-3+ \sqrt{3i}}{2}=0$

$x^2-\frac{3-\sqrt{3}i}{2}x-\frac{3+\sqrt{3}i}{2}x+\frac{9-3i^2}{4}=0$

$x^2-\frac{-6x}{2}+\frac{9-3(-1)}{4}=0$

$x^2+3x+3=0$

So,  equation has the solutions $x=\frac{-3 \pm \sqrt{3}i}{2}$ is $x^2+3x+3=0$