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PolarNik [594]
4 years ago
8

Find the future value of the annuity due for

Mathematics
1 answer:
tigry1 [53]4 years ago
4 0
Is it decreasing or incresing?
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Based on Max’s father estimate how many minutes will it take to build the box
aalyn [17]

Answer:

hh

Step-by-step explanation:

5 0
3 years ago
What is the LCD of 4, 5, and 6
Ahat [919]
Solutions 

<span>To solve the problem our first step is to find the prime factorization of each number. </span>

4 = 2² 
<span>5 = 5 </span>
<span>6 = 2 x 3 
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Calculations 

<span>LCM = 2² x 3 x 5 = 60 </span>
6 0
3 years ago
Find the slope of the line that passes through (5,12) and (9,7)
omeli [17]

The slope will be the difference between the y-coordinates divided by the difference between the x-coordinates:

then the slope of the line is:

m=\frac{12-7}{5-9}=\frac{5}{-4}=-\frac{5}{4}

8 0
1 year ago
In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.
storchak [24]

The length of q, to the nearest 10th of a centimeter is 7.6 cm.

Given in question,

In ΔOPQ,

o = 9.2 cm

p = 2.4 cm

∠Q = 37°

Cosine formula ⇒ cos θ = \frac{o^{2}+p^{2}-q^{2}  }{2op}

Putting the values in equation,

       cos 37 = \frac{(9.2)^{2}+(2.4)^{2}-q^{2}  }{2*9.2*2.4}

         0.799 = \frac{84.64 + 5.76-q^{2} }{44.16}

0.799*44.16 = 90.4 - q^{2}

         32.28 = 90.4 - q^{2}

                q^{2} = 90.4 - 32.28

                q^{2} = 58.12

                 q = \sqrt{58.12}

                 q = 7.63

q = 7.6 cm (to nearest 10th)

Hence, length of q is 7.6 cm.

Learn more about length on:

brainly.com/question/8552546

#SPJ1

3 0
2 years ago
For the given statement Pn, write the statements P1, Pk, and Pk+1.
Leno4ka [110]

Answer:

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

P_{n} as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

P_{n} as 2 + 4 + 6 + . . . + 2n = \sum_{i=1}^{n}2i

So, we have,

P_{1} = \sum_{i=1}^{1}2i = 2

P_{k} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k = k(k+1)

P_{k+1} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

7 0
3 years ago
Read 2 more answers
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