Answer:
Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.
The value of p is 0 .00233. The result is significant at p < 0.10.
Step-by-step explanation:
1) Let the null and alternate hypothesis be
H0: μboys − μgirls > 0
against the claim
Ha: μboys − μgirls ≤ 0
2) The significance level is set at 0.01
3) The critical region is z ≤ ± 1.28
4) The test statistic
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
Here p1= 397/768= 0.5169 and p2= 331/745=0.4429
pc = 397+331/768+745
pc= 0.4811
qc= 1-pc= 1-0.4811=0.5188
5) Calculations
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
z= 0.5169-0.4429/√ 0.4811*0.5188( 1/768+ 1/745)
z= 2.82
6) Conclusion
Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.
7)
The value of p is 0 .00233. The result is significant at p < 0.10.
Answer: t= 7
Step-by-step explanation:
Take 56 divided by 8 and you get the remainder of 7. So t must equal 7.
Answer:
21894
Step-by-step explanation:
So, since we want to use the distrubutive property, we ant to simplify 3,649
3000+600+40+9
now, multiply 6 to each one of those numbers:
18000+3600+240+54
add them together to get one number
21894
And that's how I think it's done.
Answer:
A = 80 S =70
Step-by-step explanation:
#Adults tickets = A
#Students tickets = S
A + S = 150
5A (means the price is $5 times the number of Adult tickets) equals the total amount for all of the Adult tickets altogether
3S (means the price is $3 times the number of Student tickets) equals the total amount for all of the students tickets altogether
5A + 3S = 610 (Means adding the total of all the student tickets plus adult tickets will equal $610 for all tickets sold)
Using both equations now, you can use substitution or elimination to solve for one of the variables. Then you can use the variable to substitute to solve the remaining one.
A + S = 150
5A + 3S = 610
Substitution:
A = 150 - S (Rearrange the first equation by moving S to the other side)
Substitute into the other equation
5 (150 - S) + 3S = 610
750 - 5S + 3S = 610 Combine like terms : -2S = -140
Solve for S = 70
Substitute into A + S = 150 A + (70) = 150
A = 80
