Answer:
30
Step-by-step explanation:
Answer:

Step-by-step explanation:
Represent
- Andy with A
- Christopher with C


Required
Determine the ratio of C to A
Ratio is represented as thus:

Rewrite as fraction

This gives

Convert L to mL




--- Approximated
Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So

Probability of a defective item being produced on the first shift:
1% of 50%. So

What is the probability that it was manufactured during the first shift?

0.2941 = 29.41% probability that it was manufactured during the first shift.
They could give to teams more than likely on an average score the whole team has done, or at least that is what they are supposed to do. but they also might award the team which had more teammates get better places. for example if party place got three people on their team but they all did 3rd then boring barn who got 1 person could possibly win if that one person gets 1st place.
Answer:
119 student tickets and 95 non-student tickets
Step-by-step explanation:
I did a trial-and-error solution.
I started with 107 students and 107 non-students:
(107*$7)+(107*$12) = $2033
It was too high, which tells us that there should be more who paid for the cheaper price.
I ended up with 119 and 95:
(119*$7)+(95*$12) = $1973