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Likurg_2 [28]
3 years ago
15

choose the point-slope form of the equation below that represents the line that passes through the point (-1,6) and has a slope

of -3
Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0
Point-slope: y-y1=slope(x-x1)
y-6=-3(x-(-1)
y-6=-3(x+1)
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JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw
luda_lava [24]

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iris [78.8K]

Answer:

<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>

Step-by-step explanation:

<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14

<em>2. Now let us break this expression into groups:  </em>

3y^2 - 6y + 7y - 14  ⇒ ( 3y^2 - 6y )( 7y - 14 )

<em>3. Factor 3y from 3y^2 - 6y:</em>

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<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>

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<em>6. Factor common term y - 2:</em>

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