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Nikitich [7]
3 years ago
8

QUICK HELP!!! How manny differences can you spot? 8 6 7 4 3 5

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0

Answer: lets see, I personally see 4 possible differences

Eduardwww [97]3 years ago
4 0

Answer:

i can only see 3

Step-by-step explanation:

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Write the following quadratic in vertex form X^2-10x+7
grin007 [14]
Hello,

y=x²-10x+7=x²-2*5x+25-25+7=(x-5)²-18
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5 0
2 years ago
Which of the following describe an angle with a vertex at E?
Marianna [84]

Answer

B., C.

Step-by-step explanation:

Since the 'E' in the middle

it represents that the angle forms at the vertex E

3 0
3 years ago
Read 2 more answers
Hellp me solve this thanks
stellarik [79]

Answer:

c. 10 cm

Step-by-step explanation:

The parallel sides of trapizium are the bases so

base 1(B1) =9cm , base(B2)= 12cm

area(a) = 105 {cm}^{2}

the perpendicular distance means the height so lets find the height

area of trapizium= <u>B1 + B2</u> × h

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2

{105cm}^{2}(the \: given \: area)  =  \frac{9cm(the \: given \: base) + 12cm(the \: given \: base)}{2}  \times h

{105cm}^{2}  =  \frac{21cm}{2}  \times h

now we crisscross

{105cm}^{2} \times 2 = 21cm \times h

{210cm}^{2}  = 21cm \times h

\frac{ {210cm}^{2} }{21cm}  =  \frac{21cm \: }{21cm}  \times h

h = 10 cm

hope u like it ‍❤️‍‍❤️‍‍❤️‍

For any question comment me

4 0
3 years ago
2. Factorise: a - b - a + b2.square ​
marshall27 [118]
A - a removes both a’s from equation, then you’re left with b + bsquared, since they are unknown values you cannot combine them, even if it is the same letter, you can only add and subtract unknown values with their same letters together.
7 0
2 years ago
Simplify fully e x e x e x f/ e x e x f x f
mel-nik [20]

Given:

The given expression is

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

To find:

The simplified form of given expression.

Solution:

We have,

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

The common factors in numerator and denominator are e, e, f.

Cancel out the common factors.

=\dfrac{e}{f}

Therefore, the required expression is \dfrac{e}{f}.

6 0
2 years ago
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