2x^2+20x=-38 divide both sides by 2
x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...
x^2+10x+25=6 now the left side is a perfect square
(x+5)^2=6 take the square root of both sides
x+5=±√6 subtract 5 from both sides
x=-5±√6 (so answer c.)
Answer:
As you have written
Z Y = 3 X Y,
It means X, Y, Z are collinear points i.e they lie in the same line or line segment.
Locating points X, Y,Z on the line
Two possibilities are possible
1. First Z, then X and then Y on the line or line segment
→ Z X + Y X= Z Y
But Z Y = 3 X Y [ Given]
→ Z X + Y X = 3 X Y
→ Z X = 3 X Y - Y X
→ Z X = 2 X Y ⇒ which is not the result.
2. 2nd Possibility
First Z, then Y and then X on the line or line segment
→ Z X = Z Y + Y X
→ Z X= 3 X Y + Y X [Z Y=3 X Y→(given)]
→ Z X= 4 X Y , Which is the result.
Answer: -3y + 8z
Step-by-step explanation:
2x -2x = 0
-2y + - y= -3y
5z + 3z= 8z
-3y + 8z
Measurement DBA must equal less than the sum of measurements 3 and 2