Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle = 
Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
If we look at the rest of the input and output, we also realize that:
output = input + 5
Thus if the input is 'n' then the output is 'n+5'
Hope that helps!
Answer: D. 94.25 in²
Step-by-step explanation:
To find the total area, we will break the shape up into two different parts.
[] The rounded part is 39.25 in². Let us assume the rounded part is exactly half of a circle.
Area of a circle:
A = πr²
Use 3.14 for pi:
A = (3.14)r²
Find the radius:
d / 2 = r, 10 / 2 = 5 in
Subsittue:
A = (3.14)(5)²
A = 78.5 in²
Divide by 2 since it is only half:
78.5 in² / 2 = 39.25 in²
[] The triangle is 55 in².
Area of a triangle:
A = b*h/2
A = 11 * 10 / 2
A = 110 / 2
A = 55 in²
[] Total area. We will add the two parts together.
55 in² + 39.25 in² = 94.25 in²
1/2 is the greater fraction
G, the y-intercept will not be 3
