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Margarita [4]
3 years ago
15

Maria is buying new carpet. Her bedroom is in the shape of a square and the length id each side is 12 feet. Write and simplify a

n exponential expression to find how much carpet she needs.
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer: She needed 144 square feet of carpet.

Step-by-step explanation:

Given : Maria is buying new carpet. Her bedroom is in the shape of a square.

The length of each side is 12 feet.

We know that the area of square = (side)^2

So , the area of the bedroom = (12)^2  [which is an exponential expression]

Simplify it

The area of the bedroom = 12\times12=144\ \text{ft}^2

Also, the carpet she needed = Area of the bedroom.

Thus , She needed 144 square feet of carpet.

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Calculate the total surface area of the triangular pyramid.
AleksandrR [38]

Answer:

45

Step-by-step explanation:

15+10= 25 + 20 = 45

3 0
2 years ago
4.9t^2-2.78t-1.15=0 what is the value of T
zzz [600]

Answer:

t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

Step-by-step explanation:

Solve for t:

4.9 t^2 - 2.78 t - 1.15 = 0

4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:

(49 t^2)/10 - (139 t)/50 - 23/20 = 0

Multiply both sides by 10/49:

t^2 - (139 t)/245 - 23/98 = 0

Add 23/98 to both sides:

t^2 - (139 t)/245 = 23/98

Add 19321/240100 to both sides:

t^2 - (139 t)/245 + 19321/240100 = 75671/240100

Write the left hand side as a square:

(t - 139/490)^2 = 75671/240100

Take the square root of both sides:

t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

3 0
2 years ago
HELP! THIS IS DUE AT 10:40!!!!!!
katrin2010 [14]

Answer:

Yes

Step-by-step explanation:

Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.

3 0
3 years ago
Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
2 years ago
Reina and Sam are multiplying (8^4)^5 (7^3)^9<br><br> Is either of them correct?
PilotLPTM [1.2K]

Answer:

Sam is correct.

Step-by-step explanation:

Exponent rules state that when an number with an exponent is raised to a power, the two exponents multiply.  For example, a^2^2=a^4.

6 0
3 years ago
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