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Karo-lina-s [1.5K]
3 years ago
12

Select the three characteristics that best describe a STEM-educated student.

Chemistry
2 answers:
vitfil [10]3 years ago
6 0

Answer:

The correct answers are "Innovative, Curious and Logical".

Explanation:

STEM education involves teaching students about four disciplines: science, technology, engineering and mathematics; initials that give the name at this type of education. Since STEM-educated students are subjected to an interdisciplinary and applied program, they need to have multiple skills. These skills include the student being Innovative, Curious and Logical; which are characteristics that a good scientist must have. Innovative to look for novel researches that have an impact on society; curious to perform additional experiments when required; and logical to analyze the data generated from the experiments and present it in scientific articles and congresses.

Lemur [1.5K]3 years ago
5 0
Innovated Understanding Curious Logical
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At 22 °C, an excess amount of a generic metal hydroxide, M(OH)2, is mixed with pure water. The resulting equilibrium solution ha
brilliants [131]

Answer:

2.29x10⁻¹² is Ksp of the salt

Explanation:

The Ksp of the metal hydroxide is:

M(OH)₂(s) ⇄ M²⁺ + 2OH⁻

Ksp = [M²⁺] [OH⁻]²

As you can see in the reaction, 2 moles of OH⁻ are produced per mole of M²⁺. It is possible to find [OH⁻] with pH, thus:

pOH = 14- pH

pOH = 14 - 10.22

pOH = 3.78

pOH = -log[OH⁻]

<em>1.66x10⁻⁴ = [OH⁻]</em>

And [M²⁺] is the half of [OH⁻], <em>[M²⁺] = 8.30x10⁻⁵</em>

<em />

Replacing in Ksp formula:

Ksp = [8.30x10⁻⁵] [1.66x10⁻⁴]²

Ksp = 2.29x10⁻¹² is Ksp of the salt

7 0
3 years ago
A hot air balloon is filled with of an ideal gas on a cool morning ( The air is heated to What is the volume of the air in the b
Leto [7]

Answer:

Charles's law states that V1 / T1 = V2 / T2. However, you must make sure that T is in Kelvin, not C.

1.19E6 / (11 + 273) = V2 / (113 + 273)

V2 = 1.62E6

Explanation:

Gases expand when heated if the container they are in is flexible. When the gas is heated its molecules move faster and faster. The collisions of the gas particles with the flexible container wall expand.

6 0
4 years ago
When magnesium ribbon is ignited, it gives off a white fume of magnesium oxide. What is this type of reaction? synthesis reactio
lapo4ka [179]
It is an oxidation reaction 

6 0
4 years ago
A 3.0-L sample of helium was placed in container fitted with a porous membrane. Half of the helium effused through the membrane
zhenek [66]

Explanation:

It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.

And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.

          \frac{1.5 L}{24 hr}

            = 0.0625 L/hr

As, molar mass of He is 4 g/mol  and molar mass of O_{2} is 32 g/ mol.

Now,

   \frac{\text{Rate of He}}{\text{Rate of Oxygen}} = \sqrt{\frac{32}{4}

                               = 2.83

or, rate of O_{2} = \frac{\text{Rate of He}}{2.83}

                       = \frac{0.0625 L/hr}{2.83}

          Rate of O_{2} = 0.022 L/hr.

This means that 0.022 L of O_{2} gas effuses in 1 hr

So, time taken for the effusion of 1.5 L of O_{2} gas is calculated as follows.

         \frac{1.5 L}{0.022 L/hr}

                = 68.18 hour

Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.

3 0
4 years ago
How many grams of O2 are needed to react with 18.2 g of NH3?
erastova [34]

Answer:

44 g oxygen are needed.

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g/ 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

                          4                 :                 5

                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.375 mol × 32 g/mol

Mass = 44 g

4 0
3 years ago
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