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Nostrana [21]
2 years ago
8

Difference between dipole dipole and hydrogen bonding

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
8 0

Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.

<h3>What is bonding in molecules?</h3>

Bonding is a type of attraction force which is present between the different atoms or elements of any substance.

  • Dipole dipole attraction force is a weak force as compared to the hydrogen bonding and present between any two oppositely charged atoms.
  • Hydrogen bond is present between the hydrogen atom and more electronegative atoms like O, S, N and F.

Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.

To know more about dipole-dipole force, visit the below link:
brainly.com/question/24197168

#SPJ4

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A hypothetical element, E, has two stable isotopes. One isotope has a natural abundance of 68.037% and has an atomic mass of 46.
I am Lyosha [343]
  • If the abundance of the first isotope is 68.037%, then the abundance of the second isotope is 100%-68.037%.

Substituting into the atomic mass formula,

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2 years ago
If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p
ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and  the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V  = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

PV=nRT

P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm

Vander wall's of equation of gases:

The real pressure of the gas= p_v

For argon:

a=1.345 L^2 atm/mol^2

b=0.03219 L/mol.

(p_v+(\frac{an^2}{V^2})(V-nb)=nRT

(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K

p_v = 47.29 atm

Difference :p - p_v= 49.28 atm - 47.29 atm = 1.99 atm\approx 2.0 atm

2.0 atm is the difference between the ideal pressure and  the real pressure.

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Answer:

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Explanation:

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