Answer:
0.478 J/g/C
Explanation:
When solving questions on heat energy, we can use the formula
Q = mcT where
Q is the amount of energy supplied in Joules
m is the mass of the object in Grams
c is the specific heat capacity of the metal in Joules Per Gram Per Degree Celcius
T is the <em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em>in Temperature in Degree Celcius.
So by applying the formula to this question, we get:
15000 = (950)(c)(78 -45)
c = <u>0.478 J/g/C</u>
Answer:
4.16 * 10²⁴ particles
Explanation:
1. We convert from grams to moles
4 g NaCl / 58 g of NaCl = 0.0689655172 moles
-> 0.0690 moles
2. Now we will convert from moles to particles by multiplying by avogadro's number..
0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles
Answer:
Part A: Hexacyanoferrate (III)
Part B: DiammintetraaquoCupperate (II)
Part C: Dichlorobis(ethylenediamine) Chromate (II)
Part D: Triaquocarbonylnickel (II) Sulphate
Part E: Potassium Dicarbonatedifluoroplatinate (II)
Explanation:
For naming the complex ions there is a specific rule
Nomenclature of the complex ions are as follow
- write a correct formulae
- Indicate the oxidation number of metal in the complex
- The oxidation number should write in the roman numeral in perenthasis after metal name
- Ligand named before the metal ion
- Ligan can be named in following order
* 1st negative, 2nd neutral, 3rd positive
* If there are more than 2 same charged ligand the write in
alphabetical order.
- Write prefix i.e di, tri, tetra for multiple monodentate ligands
- Anions name end at ido the replace the final name.
- Neutral ligands named as their usual name, but there are some exceptions such as
NH3 named as ammine
H2O names aqua or aquo
CO named ascarbonyl
NO named as nitrosyl
- If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
- The name of full complex will end with cation or anion with separate word.
Keeping the rules in mind the complexes named as following.
_________________________
Part A:
[Fe(CN)₆]³⁻
Name of the Complex : Hexacyanoferrate (III)
___________________
Part B:
[Cu(NH₃)₂(H₂O)₄]²⁺
Name of the Complex : DiammintetraaquoCupperate (II)
_______________________
Part C
CrCl₂(en)₂
Name of the Complex : Dichlorobis(ethylenediamine) Chromate (II)
________________________
Part C
[Ni(H₂O)₃(CO)]SO₄
Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate
______________________
Part E
K₄[Pt(CO₃)₂F₂]
Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)
Answer:
rate = l[A][B]
Explanation:
We are given the information that step 1: A + B → 2C + D is the the rate determinng steps, while the other 2 are fast in the reaction mechanism.
The rate law which is what we need to determine in this question is dependent on the the slowest step,
Therefore, the rate law will be a second order overall and dependent on the concentrations of A and B:
rate = k [A][B]
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