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Anika [276]
3 years ago
8

I need help with part B . please

Chemistry
1 answer:
myrzilka [38]3 years ago
8 0
So it's good to map out what you know you have and work from there:
We have two liter measurements and one mole measurement, and we need to find the moles.

For this problem, think of it this way: 46 liters of gas = 1.4 moles.
If one side changes, the other has to as well (if the liters decrease, the moles decrease. if the liters increase, so do the moles.) What you can do is put this into a fraction:

  <span><u>1.4 moles</u></span>
      46 L   <span> </span>

if we know that each liter of gas is equal to x amount of moles, we know that 11.5 liters equals some amount of moles. You can put this into a fraction too, and make it equal to the other fraction:

   <span><u>1.4 moles</u></span> = <u>x moles</u> 
         46 L         11.5 L

Then get your calculator out and do some algebra.

11.5 * (1.4/46) = x

The answer should come out to be: 0.35 moles
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7 0
3 years ago
What is the chemical name for the balanced equation? 2Al+3Pb(NO3)2=2Al(NO3)3+3Pb​
Zigmanuir [339]
  • The chemical name for reactant side:

                  Al - Aluminium, Pb(NO3)2 -  Lead(II) nitrate.

  • The chemical name for product side:

                  Al(NO3)3 - Aluminium nitrate, Pb - lead.

<u>Explanation</u>:

  • This is an oxidation-reduction (redox) reaction:

                       3 Pb^{II} + 6 e- → 3 Pb^{o} (reduction)

                       2 Al^{o} - 6 e- → 2 Al^{III} (oxidation)

Pb(NO3)2 is an oxidizing agent, Al is a reducing agent.

  • Reactants:                              

                                    Al uminium

              Names: Aluminum, Aluminium powder,  Al

              Appearance: Silvery-white-to-grey powder, Silvery-white,  

                                      malleable, ductile, odorless metal.

                             Pb(NO3)2 – Lead(II) nitrate

              Other names: Lead nitrate, Plumbous nitrate, Lead dinitrate

              Appearance: White colorless crystals,  White or colorless crystals

  • Products:

                            Al(NO3)3 – Aluminium nitrate

              Other names: Nitric Aluminum salt, Aluminum nitrate,

                                       Aluminium(III) nitrate

              Appearance: White crystals, solid | hygroscopic

                                   Pb  - lead

              Names: Lead, Lead metal, Plumbum

              Appearance: Bluish-white or silvery-grey solid in various forms.

                                     Turns tarnished on exposure to air. A heavy, ductile,

                                     soft, gray solid.

8 0
3 years ago
chemistry A basketball is inflated to a pressure of 1.10 atm in a 28.0°C garage. What is the pressure of the basketball outside
butalik [34]

Answer : The final pressure of the basketball is, 0.990 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{P_2}=\frac{T_1}{T_2}

where,

P_1 = initial pressure = 1.10 atm

P_2 = final pressure = ?

T_1 = initial temperature = 28.0^oC=273+28.0=301.0K

T_2 = initial temperature = -2.00^oC=273+(-2.00)=271.0K

Now put all the given values in the above equation, we get:

\frac{1.10atm}{P_2}=\frac{301.0K}{271.0K}

P_2=0.990atm

Thus, the final pressure of the basketball is, 0.990 atm

7 0
3 years ago
Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after
Alenkinab [10]

<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature of the air = 37^oC=[37+273]K=310K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of air = ?

Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

Hence, the number of moles of air present in the RV is 0.047 moles

  • <u>For b:</u>

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

7 0
3 years ago
An independent variable is....
Irina18 [472]

Answer:

B - What we change

Explanation:

Dependent Variable - What we measure

Control Variable - what stays the same

Conclusion - what we conclude

<em>Hope</em><em> </em><em>this</em><em> </em><em>can</em><em> </em><em>Help</em><em>!</em>

<em>:</em><em>D</em>

5 0
3 years ago
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