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Anika [276]
3 years ago
8

I need help with part B . please

Chemistry
1 answer:
myrzilka [38]3 years ago
8 0
So it's good to map out what you know you have and work from there:
We have two liter measurements and one mole measurement, and we need to find the moles.

For this problem, think of it this way: 46 liters of gas = 1.4 moles.
If one side changes, the other has to as well (if the liters decrease, the moles decrease. if the liters increase, so do the moles.) What you can do is put this into a fraction:

  <span><u>1.4 moles</u></span>
      46 L   <span> </span>

if we know that each liter of gas is equal to x amount of moles, we know that 11.5 liters equals some amount of moles. You can put this into a fraction too, and make it equal to the other fraction:

   <span><u>1.4 moles</u></span> = <u>x moles</u> 
         46 L         11.5 L

Then get your calculator out and do some algebra.

11.5 * (1.4/46) = x

The answer should come out to be: 0.35 moles
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15000 joules is used to heat a 950g piece of metal from 45 degrees Celsius to 78 degrees Celsius what is the specific heat of th
castortr0y [4]

Answer:

0.478 J/g/C

Explanation:

When solving questions on heat energy, we can use the formula

Q = mcT where

Q is the amount of energy supplied in Joules

m is the mass of the object in Grams

c is the specific heat capacity of the metal in Joules Per Gram Per Degree Celcius

T is the <em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em>in Temperature in Degree Celcius.

So by applying the formula to this question, we get:

15000 = (950)(c)(78 -45)

c = <u>0.478 J/g/C</u>

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3 years ago
How many particles are in 4g of NaCl? (1mol of NaCl = 58g) – 2 step conversion
oksian1 [2.3K]

Answer:

4.16 * 10²⁴ particles

Explanation:

1. We convert from grams to moles

4 g NaCl / 58 g of NaCl = 0.0689655172 moles

-> 0.0690 moles

2. Now we will convert from moles to particles by multiplying by avogadro's number..

0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles

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3 years ago
Part A Name the complex ion [Fe(CN)6]^3- . The oxidation number of iron is +3. Part B Name the complex ion [Cu(NH3)2(H2O)4]^2+ .
zvonat [6]

Answer:

Part A: Hexacyanoferrate (III)

Part B: DiammintetraaquoCupperate (II)

Part C: Dichlorobis(ethylenediamine) Chromate (II)

Part D: Triaquocarbonylnickel (II) Sulphate

Part E: Potassium Dicarbonatedifluoroplatinate (II)

Explanation:

For naming the complex ions there is a specific rule

Nomenclature of the complex ions are as follow

  • write a correct formulae
  • Indicate the oxidation number of metal in the complex
  • The oxidation number should write in the roman numeral in perenthasis after metal name
  • Ligand named before the metal ion
  • Ligan can be named in following order

                  * 1st negative,  2nd neutral, 3rd positive

                  * If there are more than 2 same charged ligand the write in                      

                    alphabetical order.

  • Write prefix i.e di, tri, tetra for multiple monodentate ligands
  • Anions name end at ido the replace the final name.
  • Neutral ligands named as their usual name, but there are some exceptions such as

                                      NH3 named as ammine

                                      H2O names aqua or aquo

                                     CO named ascarbonyl

                                      NO named as nitrosyl

  • If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
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Keeping the rules in mind the complexes named as following.

_________________________

Part A:

[Fe(CN)₆]³⁻

Name of the Complex : Hexacyanoferrate (III)  

___________________

Part B:

[Cu(NH₃)₂(H₂O)₄]²⁺

Name of the Complex : DiammintetraaquoCupperate (II)

_______________________

Part C

CrCl₂(en)₂

Name of the Complex :  Dichlorobis(ethylenediamine) Chromate (II)

________________________

Part C

[Ni(H₂O)₃(CO)]SO₄

Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate

______________________

Part E

K₄[Pt(CO₃)₂F₂]

Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)

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Answer:

rate = l[A][B]

Explanation:

We are given the information that step 1:  A + B → 2C + D is the the rate determinng steps, while the other 2 are fast in the reaction mechanism.

The rate law which is what we need to determine in this question is dependent on the  the slowest step,  

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