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Fantom [35]
3 years ago
7

If the function f(x)= 3/2x-10 were graphed, which of the following would be true? A. All the y-values would be negative. B. As t

he x-values increase, the y-values would increase. C. All the x-values would be negative. D. As the x-values increase, the y-values would decrease.
Mathematics
1 answer:
irga5000 [103]3 years ago
7 0
Df/dx=3/2=1.5  so this line has a positive constant rate of change.  y increases by 1.5 for every 1 increase in x.

So B. is the only true statement as y values increase as x values increase.
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Find the 11th term of the arithmetic sequence an=<br> 24 – 7(n - 2)<br> 2115
sweet [91]

Answer:

Let's simplify

24−7(n−2)(2115)

Step-by-step explanation:

step-by-step.

=−14805n+29634

I hope my answer helped

7 0
3 years ago
Please help would mean a lot
sammy [17]

Answer:

C maybe.........

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Algebra Review: Pra<br> (4x-7)(2x+1)
ki77a [65]
2x - 6 = 2 • (x - 3)
2 = 0
x-3 = 0
x=3
7 0
3 years ago
gina pasted 3 stickers in a book. if she added one sticker to her collection every day, what equation represents the relationshi
lukranit [14]

Answer:

The answer to your question is

                       Number of stickers = number of days + 3

Step-by-step explanation:

- To find the equation of the line that represents the situation, first, find the slope.

Slope = m = \frac{y2 - y1}{x2 - x1}

             m = \frac{4 - 3}{1 - 0} = \frac{1}{1} = 1

- Find the equation of the line

                      y - y1 = m(x - x1)

                      y - 4 = 1(x - 1)

                      y - 4 = x - 1

                           y = x - 1 + 4

                           y = x + 3

y = number of stickers

x = days

                     Number of stickers = number of days + 3

3 0
3 years ago
CAN SOMEONE GIVE ME THE STEPS I HAVE THE ANSWERS I JUST NEED THE STEPS
natali 33 [55]

Problem 1:

1) 3/5x-1 x 3/4=9/10

3x/5-1 x 3/4=9/10

2) 3x/5-1 x 3/4=9/10

3x/5-3/4=9/10

3) 3x/5-3/4=9/10

+3/4 +3/4

4) 3x/5=33/20

5) 5 x 3x/5= 5 x (33/20)

6) 3x=33/4

7) 3x=33/4

/3 /3

8) x=11/4

Problem 2:

1) 6/7+2/5x=-4/5

6/7+2x/5=-4/5

2) 6/7+2x/5=-4/5

-6/7 -6/7

3) 2x/5= --58/35

4) 5 x 2x/5= 5 x (--58/35)

5) 2x= --58/7

6) 2x= --58/7

/2 /2

x= --29/7

3 0
3 years ago
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