Question

Suppose two adjacent endpoint of a rotated square are located at (-4, -6) and (5, -1) on the coordinates axes. What is the length of the side of the square?

Answer 1

To find the length of side of square, we have to use distance formula.
Points are (-4,-6) and (5,-1)
Formula for distance between two points.
$d= \sqrt{( x_{2}-x_1 )^2+(y _2-y_1)^2 } \\ Put \ values \\ d= \sqrt{( 5+4)^2)+(-1+6)^2 } \\ d= \sqrt{( 9)^2)+(5)^2 } \\ d=\sqrt{106} \\ d=10.3 \ units$
So length of side of square is 10.3 units.

Answer: 10.3 units