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Sphinxa [80]
3 years ago
8

How do you solve C-5 when C=15

Mathematics
2 answers:
Anna007 [38]3 years ago
7 0
Plug in 15 for C 
15-5 = 10
Paha777 [63]3 years ago
5 0
So it would be 10
hope it helped
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You roll a fair 6 sided dice. What is p(not 5)?
liq [111]

Answer:

p(not 5) = 5/6

Step-by-step explanation:

The probability that we roll a 5 is 1/6. So, the probability we don't roll a five is simple 1 minus that:

1-\frac{1}{6} = \frac{5}{6}

And that's your answer.

7 0
3 years ago
arts and crafts shop has a bolt of crimson velvet 32 M long a customer came in during the morning and bought 120cm of the velvet
deff fn [24]

Answer:

2760

Step-by-step explanation:

I really don't know I just did 32x120

6 0
3 years ago
Please help! (Also show work)<br> Tutorials :D
oksano4ka [1.4K]

The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

<h3>How to Find the Five-number Summary of a Data?</h3>

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

  • Minimum value: this is the smallest lengths, which is 9
  • First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.
  • Median: the median is the center of the data distribution which is 25.5.
  • Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.
  • Maximum: this is the largest length in minutes, which is, 51.

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

Learn more about the five-number summary on:

brainly.com/question/24809873

#SPJ1

6 0
1 year ago
No question........................
frutty [35]

Answer:

Step-by-step explanation:

ok

8 0
3 years ago
Read 2 more answers
A camp ground consists of 12 square campsites arranged in a line along a beach. The distance from the edge of a campsite to the
Darina [25.2K]
X=side length of a campsite
12x(5+x)=1248  because each campsite has a length of x and there are 12                           and from the top of the camp to the water is the 5 yds + a                             side length and LW=1248
60x+12x^2=1248
12x^2+60x-1248=0
x^2+5-14=0
(x+7)(x-2)=0
x+7=0 or x-2=0
x=-7 or x=2
x=2 because width can't be negative
the width of one campsite is 2 yds
4 0
3 years ago
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