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Mamont248 [21]
3 years ago
10

The manager of a store increases the price of a popular product by 5%. Let t be the original price of the product. The new price

is t + 0.05t. Find an expression equivalent to t + 0.05t. If the original price was $24, what is the new price?
Mathematics
2 answers:
Leviafan [203]3 years ago
7 0
The new price would be $25.2 so $25 and 20 cents!!
valentinak56 [21]3 years ago
5 0
The equivalent expression is 1.05t and then 24 x 0.05 equals 1.2 so 25.2
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Answer

given,

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now,

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assuming these are the points on the demand curve

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using point slope formula

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p-50 = \dfrac{-x}{100}+ 40

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R(x) = x . p

R(x) = x (\dfrac{-x}{100}+ 90)

R(x) = \dfrac{-x^2}{100}+ 90x)

\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))

\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)

at \dfrac{d}{dx}(R(x)) = 0

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hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

p = \dfrac{-4500}{100}+ 90

p = $45

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Step-by-step explanation:

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