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chubhunter [2.5K]
3 years ago
7

How to work out arc length and sector area

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0
You can work out<span> the </span>arc length<span> using the</span>formula<span> (Angle/360)*2*Pi*r. So all you have to do is substitute the angle and radius into this</span>formula<span> to </span>work out<span> the </span>arc length<span>. In example 1, you need to </span>work out<span> the </span>arc length<span> of a</span>sector<span> with a radius of 6 cm and an angle of 42 degrees. hope it helps

</span>
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A yoga membership costs $16 and an additional $7 per class. write a linear equation modeling the cost of a yoga membership.
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Y=16x+7
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The total area of the shape is 32
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PLEASE HELP ASAP WILL GIVE BRAINLIEST!!!!
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Answer:

Step-by-step explanation:

y intercept is -6

the slope is already in it's fraction form but if you want it back to whole number it's y=1.33x-6

the slope is positive

Some plots you can put are (6, 2) and (12, 10)

Just start at (0, -6) and counts 4 up and 3 right

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A ′ B ′ C ′ triangle, A, prime, B, prime, C, prime is the image of △ A B C △ABCtriangle, A, B, C under a rotation about the orig
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The angle of rotation of triangle ABC to A'B'C is 105°

<h3>How to illustrate the information?</h3>

It should be noted that the rotation from ABC to A'B'C is in a clockwise direction.

Point B is also on the x axis and point B' is in the second quadrant.

In this case, the angle that depicts the second quadrant is 105°.

In conclusion, the correct option is D.

The complete question is:

Triangle A’ B’ C’ is the image of A B C under a rotation about the origin, (0,0)

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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
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Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

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3 years ago
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