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xz_007 [3.2K]
3 years ago
6

Let the joint pdf of X andY be f(x,y) = 12e−4x−3y , x > 0, y > 0.

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

Step-by-step explanation:

Find attached the solution

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Ew i hate these⇆∈√,×≈↓⇒∈∧⊂∴∵√²³Ф≠→Ф
5 0
3 years ago
Is anyone wanna help me?
PtichkaEL [24]

Answer:

See the answers bellow

Step-by-step explanation:

For 51:

Using the definition of funcion, given f(x) we know that different x MUST give us different images. If we have two different values of x that arrive to the same f(x) this is not a function. So, the pair (-4, 1) will lead to something that is not a funcion as this would imply that the image of -4 is 1, it is, f(-4)=1 but as we see in the table f(-4)=2. So, as the same x, -4, gives us tw different images, this is not a function.

For 52:

Here we select the three equations that include a y value that are 1, 3 and 4. The other values do not have a y value, so if we operate we will have the value of x equal to a number but not in relation to y.

For 53:

As he will spend $10 dollars on shipping, so he has $110 for buying bulbs. As every bulb costs $20 and he cannot buy parts of a bulb (this is saying you that the domain is in integers) he will, at maximum, buy 5 bulbs at a cost of $100, with $10 resting. He can not buy 6 bulbs and with this $10 is impossible to buy 0.5 bulbs. So, the domain is in integers from 1 <= n <= 5. Option 4.

For 54:

As the u values are integers from 8 to 12, having only 5 possible values, the domain of the function will also have only five integers values, With this we can eliminate options 1 and 2 as they are in real numbers. Option C is the set of values for u but not the domain of c(u). Finally, we have that 4 is correct, those are the values you have if you replace the integer values from 8 to 12 in c(u). Option 4.

6 0
3 years ago
WILL GIVE BRAINLEIST SUPER EASY NEED TO TURN IN BY 9:45 PLS HURRY.
ki77a [65]

Answer:

144 cookies

Step-by-step explanation:

Since the 3 dozen cookies she baked was 1/4th the amount in total, all you have to do to find the total amount is multiply the fraction of the cookies 3 dozen (36) by 4.

36×4 = 144 cookies in total

6 0
3 years ago
Please Help!
Flura [38]
Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s
8 0
3 years ago
I need help with this Algebra 1 Study Guide. It has 5 questions . This has many hard questions so to you people that like a chal
scoundrel [369]
1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational.  Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. <span>√4 = 2, rational.</span>

√4 + <span>√16 = 2 + 4 = 6. rational
</span>√5 + √36...<span> irrational
</span>√9 + <span>√24... irrational
</span>2 × <span>√4 = 2 × 2 = 4. rational
</span>√49 × <span>√81 = 7 × 9 = 63. rational
</span>3√12... irrational

2. n^\frac12=\sqrtn
9^\frac32=9^3\times\frac12=\sqrt{9^3}=\sqrt{729}=29

3. \frac{n^a}{n^b}=n^{a-b}

\frac{a^\frac13}{a^\frac14}=a^{\frac13-\frac14}=a^{\frac{1}{12}}

4. n^\frac1x=\sqrt[x]n

\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}

5. \sqrt{a}\times\sqrt{b}=\sqrt{ab}

\sqrt{3}\times\sqrt{12}=\sqrt{3\times12}=\sqrt{36}=6

A, since neither 3 nor 12 is a square but we end up with 6.
5 0
3 years ago
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