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Yuki888 [10]
3 years ago
7

Rewrite the expression as an algebraic expression in x. cos(tan−1 x)

Mathematics
1 answer:
zhenek [66]3 years ago
7 0
It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes:  "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

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Wesley willed his estate to Margaret,
DiKsa [7]

Answer:

1,100,000

Step-by-step explanation:

20000 + 22(20000) + 32 (20000)= 55 (20000)= 1,100,000

4 0
3 years ago
Read 2 more answers
Practice 7) fill in the blanks.
DiKsa [7]

(h,k) is the vertex

b/2a is the line of symmetry

a > 0 parabola opens upward, vertex is a minimum

a < 0 parabola opens downward, vertex is a maximum

My first answer was deleted lolol

7 0
3 years ago
The minor arc measures of circle Z are shown in the figure.
DerKrebs [107]

The completed statement are:

  • Angle UZT is congruent to angle TZY.
  • Angle VZW is congruent to angle YZX.

<h3>What is the angle about?</h3>

Part A:

Angle UZT is congruent to angle TZY.

Using the image attached figure, we can see that:

∠UZT = 54°

∠TZY = 54°

Hence one can say that ∠TZY = ∠UZT are both congruent angles.

Part B:

Angle VZW is congruent to angle YZX.

Using the image attached attached, we can see that:

∠VZW = 71°

∠YZX = 71°

Hence, ∠YZX = ∠VZW are both  regarded as congruent angles .

Therefore, The completed statement are:

  • Angle UZT is congruent to angle TZY.
  • Angle VZW is congruent to angle YZX.

Learn more about Angles from

brainly.com/question/14684194

#SPJ1

6 0
2 years ago
Pls help answer question in picture
spayn [35]

Step-by-step explanation:

2 1/3

=2*3+1/3

=7/3

7 0
3 years ago
A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.
kenny6666 [7]

Answer:

p:y = 3x-10

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

y - y_1 = m(x - x_1)

The point intercept form of line can be written as:

y = mx + c

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10

which is the required slope intercept equation of line p.

4 0
3 years ago
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