Rewrite the expression as an algebraic expression in x. cos(tan−1 x)

1 answer:

7 0

It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes: "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

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What is 3368 ÷12<br>give an explanation for your answer make sure to try and work it out

grandymaker [24]

Answer:

280.6 repeating

Step-by-step explanation:

I attached an image of how to do the division. It is kind of difficult to explain like this.

3 0

2 years ago

What is the equation of the line that passes through (0,3) and (-5,3)

ddd [48]

Answer:

y=+3

Step-by-step explanation:

the equation of a line is y=mx+c

where m is the slope and c is the y-intercept.

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=3.

Also, let's call the second point you gave, (-5,3), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=3.

Now, just plug the numbers into the formula for m above, like this:

m= $\frac{3-3}{-5-0}$

m= $\frac{0}{-5}$

m=0

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+c like this:

y=0x+c

Now, what about c, the y-intercept?

To find c, think about what your (x,y) points mean:

(0,3). When x of the line is 0, y of the line must be 3.

(-5,3). When x of the line is -5, y of the line must be 3.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=0x+c. c is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,3) and (-5,3).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for c for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(0,3). y=mx+c or 3=0x 0+c, or solving for c: c=3-(0)(0). c=3.

(-5,3). y=mx+c or 3=0x -5+c, or solving for c: =3-(0)(-5). c=3.

See! In both cases we got the same value for c. And this completes our problem.

The equation of the line that passes through the points

(0,3) and (-5,3)

y=+3

Hope this helps :)

7 0

3 years ago

Read 2 more answers

What is 9+10 *hint its a vine*