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3 years ago

Rewrite the expression as an algebraic expression in x. cos(tan−1 x)

1 answer:

7 0

It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes: "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

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The graph below shows how far a ship is traveling in a certain amount of time.

olga2289 [7]

Answer:

100 miles

Step-by-step explanation:

Remark

All you need do is start at 4 hours on the y axis and go right until you hit a dot. When you do, go down until you hit a number on the x axis.

It helps if you mark up the graph.

Go right from 4

You hit a dot

Look down.

You should see 100. That's how far you go in 4 hours.

Note

This is an odd graph. Usually time is on the x axis.

5 0

3 years ago

Cleveland and his family are on a road trip. If they have traveled 1/2 of the total distance in the past 4 days, what fraction o

tia_tia [17]

Answer:

1/8

Step-by-step explanation:

8 0

2 years ago

What is <br><img src="https://tex.z-dn.net/?f=%20%7B5%7D%5E%7B2%7D%20%20%2B%203%20%5Ctimes%2016" id="TexFormula1" title=" {5}^{2

enyata [817]

The answer 73 because you is supposed to use your order of operations so in other words your supposed to use PEMDAS

6 0

4 years ago

Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.

makkiz [27]

Can't be done without knowing what $f$ is...

But I can tell you that the average value of $f$ is given by

$\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}$

At the very least, we can compute the denominator, which is just the area of $R$ . You have

$\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12$

so the average value will be

$2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy$

4 0

4 years ago

How can i solve this? I've looked at countless videos and nothing helps.

Andrej [43]

Let $x$ be the number of lower-level tickets sold, and $y$ the number of upper-level tickets sold.

Now, if the theater sells 350 tickets total, that means the number of lower-level and upper-level tickets that got sold should add up to 350, so one equation in the system is

$x+y=350$

You also know that the theater earns $10250 in sales, so if each lower-level ticket costs $35, and each upper-level ticket costs $25[/tex], this means $35x$ represents the amount of money made from selling lower-level ticekts, and $25y$ represents the amount of money made from selling upper-level tickets. You get the second equation in the system,

$35x+25y=10250$

So the system is

$\begin{cases}x+y=350\\35x+25y=10250\end{cases}$

Any one of the methods listed in the second part works in solving this system (though I'm not sure what "variable" refers to), but I think substituting involves the least work.

Solve the first equation for either variable; I'll choose $x$ .

$x+y=350\implies x=350-y$

Now substitute this into the second equation for $x$ , then solve for $y$ .

$35(350-y)+25y=10250\implies 10y=2000\implies y=200$

So 200 upper-level seats were sold. Meanwhile, since $x+y=350$ , this means

$x+200=350\implies x=150$

so that 150 lower-level tickets were sold.

6 0

3 years ago