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Yuki888 [10]
3 years ago
7

Rewrite the expression as an algebraic expression in x. cos(tan−1 x)

Mathematics
1 answer:
zhenek [66]3 years ago
7 0
It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes:  "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

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Evaluate (2 - 5i)(p + q)i when p = 2 and q = 5i<br>a. 29i<br>b. 291-20<br>C.-21i<br>d.29​
attashe74 [19]

Answer:

A. 29i

Step-by-step explanation:

Step 1: Plug in given variables

(2 - 5i)(2 + 5i)i

Step 2: Difference of squares (expand)

(4 - 25i²)i

Step 3: Imaginary numbers rules

(4 - 25(-1))i

Step 4: Combine like terms

(4 + 25)i

(29)i

Your final answer will be 29i

8 0
3 years ago
Read 2 more answers
The chess club members bought six tickets to a tournament for $15. how much would they have paid if all nine members wanted to g
ElenaW [278]
15/6=2.5
2.5x9=22.5
$22.50 is your answer

5 0
2 years ago
Two circles have the same radius. Is the combined area of the two circles the same as the area of a circle with twice the radius
Dimas [21]
Ok so area=pir^2

2 circles with same area=2pir^2

circle with 2 times radius=pi(2r)^2=pi4r^2=4pir^2

is 2 circles with same area equal to circle with 2 times radius?
is 2pir^2=4pir^2?
is 2=4?
no


therfor the answer is no

it is because the radius is squaered so the doubled gets doubled makng it quadrupuled when the first one only gets doubled
8 0
3 years ago
Pascal wants to ride his bike to and from school 3 days a week. His house is 2.58 kilometers from his school. How many meters wi
klemol [59]

Answer:

I thi k the answers is 108.36

5 0
3 years ago
If the distance traveled is (4s3 - 6s² + 4s + 14) miles and the rate is (s + 1) mph, write an expression, in hours, for the time
BartSMP [9]

The equation for time is URM:

time =  \frac{distance}{speed \: (rate)}

t(s) =  \frac{4s {}^{3}  - 6s {}^{2}  + 4s + 14}{s + 1}  =  \frac{2(s + 1)(2s {}^{2} - 5s + 7) }{s + 1}  \\  t(s) = 2(2s {}^{2}  - 5s + 7) \\ t(s) = 4s {}^{2}  - 10s + 14

3 0
10 months ago
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