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True [87]
3 years ago
7

Find the volume of the sphere. express your answer in term of Pie​

Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

\large\boxed{36\pi}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

R - radius

We have R = 3 ?. Substitute

V=\dfrac{4}{3}\pi(3^3)=\dfrac{4}{3}\pi(27)=(4)\pi(9)=36\pi

If the radius is 30, then the volume is:

V=\dfrac{4}{3}\pi(30^3)=\dfrac{4}{3}\pi(27,000)=(4)\pi(9,000)=36,000\pi

If 30 is the length of diameter, then the radius R = 30 : 2 = 15.

Therefore the volume:

V=\dfrac{4}{3}\pi(15^3)=\dfrac{4}{3}\pi(3,375)=(4)\pi(1,125)=4,500\pi

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Distributeiv poepty
a(b+c)=ab+ac

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SO
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3 0
3 years ago
The price of a dress is reduced by 60%.When the dress still does not​ sell, it is reduced by 60% of the reduced price. If the pr
Nina [5.8K]

Answer:

1. $450

2. $128

Step-by-step explanation:

1. new price = .4 (.4 * original price x)

72 = .16x

x = 450

2. new price = .75 (.75 * original price x)

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6 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
On a coordinate plane, a curved line crosses the x-axis at (negative 1, 0) and the y-axis at (0, 2).
telo118 [61]

Answer:

Step-by-step explanation: the answer is you 0,7

4 0
3 years ago
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OR
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7 0
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