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cestrela7 [59]
2 years ago
13

The sum of the digits of a two-digit number is 11.

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
3 0

Answer:

8 and 3

Step-by-step explanation:

8+3=11

8-3= 5

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There are 42 males and 67 females participating in a marathon. What percent of the participants are male?
Sergio039 [100]

First, you find the total of both sides.

42 + 67 = 109

Next, you divide the Total by either of the sides, but since we're looking for the percentage of males, it'd be better to do this.

42/109 = 0.39

Multiply it by 100 to change it into percentage form.

0.39 x 100 = 39%

There your answer is 39%

4 0
3 years ago
Kevin has $100 in a savings account that earns 10% annually. The interest is not compounded. How much will he have in 2 years?
Kisachek [45]
He will have 220 that is how much he will have
5 0
3 years ago
Ethan and Layla work at a furniture store. Ethan is paid $235 per week plus 9.5% of his total sales in dollars, xx, which can be
kobusy [5.1K]

Answer:

  $18,200

Step-by-step explanation:

We want ...

  f(x) = g(x)

  53 +.105x = 235 +.095x . . . . use given expressions

  .01x = 182 . . . . . . .  subtract 53+.095x

  x = 182/.01 = 18200 . . . . . divide by the coefficient of x

Each must sell $18,200 for their weekly pay to be the same.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%20x%20%5E%7B3%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ - x ^{3} } " alt=
noname [10]

I'm guessing you're given the function y(x)=2-x^3, and you're asked to find the inverse function y^{-1}(x). To do this, swap x and y, then solve for y:

x=2-y^3\implies y^3=2-x\implies y=(2-x)^{1/3}=\sqrt[3]{2-x}

so that the inverse function is

y^{-1}(x)=\sqrt[3]{2-x}

Just to verify:

y(y^{-1}(x))=y(\sqrt[3]{2-x})=2-(\sqrt[3]{2-x})^3=2-(2-x)=x

y^{-1}(y(x))=y^{-1}(2-x^3)=\sqrt[3]{2-(2-x^3)}=\sqrt[3]{x^3}=x

But in case you're actually only interested in computing the square root, first we note that \sqrt x (the real-valued square root) is only defined as long as x\ge0. So \sqrt{-x^3} is defined as long as -x^3\ge0, or x^3\le0, or equivalently x\le0. Under this condition, we could write

\sqrt{-x^3}=\sqrt{-x\times x^2}=\sqrt{-x}\sqrt{x^2}

We can simplify this further, but we have to be careful. Suppose x=-1. Then x^2=(-1)^2=1. But we get the same result if x=1, since x^2=1^2=1. There are two possible values of x that given the same value of x^2, so to capture both of them, we take \sqrt{x^2}=|x|, the absolute value of x. Then

\sqrt{-x^3}=|x|\sqrt{-x}

We can't simplify the square root term further than this.

3 0
3 years ago
Find the area of the figure. Use 3.14 for it.
Orlov [11]

Answer:

32 m squared

Step-by-step explanation:

Add 2 sides then it'll be squared for the area

6 0
3 years ago
Read 2 more answers
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