Given:
The figure of a right angle triangle.
Hypotenuse = 
in.
To find:
The missing lengths of the sides.
Solution:
In the given right angle triangle both legs a and b are equal, and hypotenuse is in.
Using Pythagoras theorem, we get
![[\because a=b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%3Db%5D)
Divide both sides by 2.
Taking square root on both sides.
Side cannot be negative. So,
Thus, the missing side lengths are a=9 in and b=9 in.
Therefore, the correct option is C.
Answer:
Step-by-step explanation:
SIDE OF THE SQUARE = 6 cm = DIAMETER OF THE CIRCLE.
AREA OF THE CIRCLE = (Pi/4)*6^2 = [(22/7)/4]*36 = 22*9/7 = 28.2857 sqcm
or
First, find the side length of the square. (Find the square root of 36 cm^2, to get 6 cm as the side length of the square).
Second, find the radius of the circle inside the square. The side length of the square is the diameter of the circle. Radius is half of the diameter. So, half of 6 cm is 3 cm; this is the radius of the circle.
Third, find the area of the circle by using the formula, A = pi x radius x radius
so, Area = 3.14 x 3 cm x 3 cm
by calculation we get the area of the circle is 28.26 cm^2
Where pi is a constant of 22/7 or 3.14
Answer:
(x+6)(x+6)
(x+6)^2
Always remember this identity
(a+b)^2 = a^2 + b^2 + 2ab
So, Now take x=a , 6 =b
Substitute above values
x^2 + 36 +2(x)(6)
=x^2 +36 +12x
=x(x+12) +36
Answer:
x = 6•3 == 18
18² = 324
324 + 2 + 11 = 337
<h2>337</h2>
Step-by-step explanation:
Order of Operations; PEMDAS
Parentheses
Exponents
Multiplication <u>& Division</u> <em>(Left to Right) (ex: 10x2÷5) You would do whatever comes left for Multiplication or Division.</em>
Addition <u>& Subtraction</u> <em>(Left to Right) (ex: 10-2+5) You would do whatever comes left for Addition & Subtraction.</em>
