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Andrei [34K]
3 years ago
12

A marching band wants to line up for their performance. When they line up in threes there are 2 left over. When they line up in

fours there are 3 left over. When they line up in fives there are 4 left over. When they line up in sixes there are 5 left over.
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer: They are 59 members in the band

Step-by-step explanation:

given data:

when lined up in 3 = 2 left.

when lined up in 4 = 3 left

when they are lined up in 5 = 4 left

when they are lined up in 6 = 5 left

Solution:

From the given data, we know the band number ends with 9, so we start with 9,29,49,59. We test till we arrive at our desired answer.

59/3 = 19 R 2.

59/4 = 14 R 3.

59/5 = 11 R 4.

59/6 = 9 R 5.

They are 59 members in the band.

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1/8 bowl.
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3 years ago
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Answer:

9(x+3) + 2(x+3) or 10(x+2) +(x+5)

Step-by-step explanation:

First you want to distribute the equation.

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Now we add like terms so it comes out to

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Two expressions that can come out to equal 11x + 25 is. 9(x+3) + 2(x+3) or 10(x+2) +(x+5)

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a worker A finishes a project on his own in 12 days. the worker completes the same work alone in 16 days. the two workers starte
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Answer:

<em>Worker B needs 9 days to finish the rest of the work</em>

Step-by-step explanation:

<u>Proportions</u>

Worker A finishes a project on his own in 12 days and worker B does the same in 16 days.

Worker A does 1/12 of the project in one day and worker B does 1/16 of the project in one day. When working together, they do

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After 3 days they have completed:

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1-\frac{7}{16}=\frac{9}{16}

parts of the project and it is done by B alone. Since B does \frac{1}{16} per day, he now takes

\displaystyle \frac{\frac{9}{16}}{\frac{1}{16}}=9

days to complete the project.

Worker B needs 9 days to finish the rest of the work

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