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Andrei [34K]
3 years ago
12

A marching band wants to line up for their performance. When they line up in threes there are 2 left over. When they line up in

fours there are 3 left over. When they line up in fives there are 4 left over. When they line up in sixes there are 5 left over.
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer: They are 59 members in the band

Step-by-step explanation:

given data:

when lined up in 3 = 2 left.

when lined up in 4 = 3 left

when they are lined up in 5 = 4 left

when they are lined up in 6 = 5 left

Solution:

From the given data, we know the band number ends with 9, so we start with 9,29,49,59. We test till we arrive at our desired answer.

59/3 = 19 R 2.

59/4 = 14 R 3.

59/5 = 11 R 4.

59/6 = 9 R 5.

They are 59 members in the band.

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Which function is an odd function?
Mrac [35]

Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

Step-by-step explanation:

7 0
3 years ago
The mass, m kilograms, of a horse is 429 kg, correct to the nearest kilogram.
Liula [17]

Answer:

400 < m< 430 kg

Step-by-step explanation:

the mass of horse is 429 kg

estimated to the nearest hundred is 400  kg

estimated to the nearest  tens is 430 kg

thus the value of m mass lies between 400 to 430

therefore

400 < m< 430 kg

6 0
1 year ago
Read 2 more answers
What is the product?<br><br> (5r − 4)(r2 − 6r + 4)
maxonik [38]

Answer:

1r

Step-by-step explanation:

(5r-4)(2r-6r+4)

1(5r-4)+1(2r-6r+4)

5r-4+2r-6r+4

5r+2r-6=1r

1r-4+4

-4+4=0

1r

7 0
1 year ago
The sum of two consecutive odd integers is 84. Find the two integers.
Rudik [331]

Answer: n + (n + 2) = 84

Step-by-step explanation:

If n is the smallest integer, the other integer must be two more than that, because it has to be odd. The two numbers add up to 84, so the other side of the equation is 84.

5 0
3 years ago
Read 2 more answers
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
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