X+y=12 -- 1
3x+2y=29 -- 2
(1)x2
2x+2y=24 -- 1
(2)-(1)
x=5
Sub x into 1
x+y=12
5+y=12
y=7
Her two numbers are 5 and 7
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
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B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
Answer:
It would be A!
Step-by-step explanation:
.08 times .50 would be 0.04. (It's a quick way to be able to solve problems similar to that! :)
Your answer would be 600. all u have to do is multiply the degree rotation to the radius.
hope this has helped.