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Andrews [41]
3 years ago
9

a worker A finishes a project on his own in 12 days. the worker completes the same work alone in 16 days. the two workers starte

d working together, but after 3 days A leaves and B. continues on his own. How many days will B need to finish the rest of the work?
Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

<em>Worker B needs 9 days to finish the rest of the work</em>

Step-by-step explanation:

<u>Proportions</u>

Worker A finishes a project on his own in 12 days and worker B does the same in 16 days.

Worker A does 1/12 of the project in one day and worker B does 1/16 of the project in one day. When working together, they do

\frac{1}{12}+\frac{1}{16}=\frac{7}{48}

After 3 days they have completed:

3*\frac{7}{48}=\frac{7}{16}

parts of the project, this means it still remains:

1-\frac{7}{16}=\frac{9}{16}

parts of the project and it is done by B alone. Since B does \frac{1}{16} per day, he now takes

\displaystyle \frac{\frac{9}{16}}{\frac{1}{16}}=9

days to complete the project.

Worker B needs 9 days to finish the rest of the work

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